How to correctly generate SHA-256 checksum for a string in scala?

Question

I need to generate an SHA-256 checksum from a string that will be sent as a get param.

If found this link to generate the checksum.

Genrating the checksum like so:

  val digest = MessageDigest.getInstance("SHA-256");      
  private def getCheckSum() = {
    println(new String(digest.digest(("Some String").getBytes(StandardCharsets.UTF_8))))        
  }

prints checksum similar to this:

*║┼¼┬]9AòdJb:#↓o6↓T╞B5C♀¼O~╟╙àÿG

The API that we need to send this to says the checksum should look like this:

45e00158bc8454049b7208e76670466d49a5dfb2db4196

What am I doing wrong?

Please advise. Thanks.

She message digest will return raw bytes. You expected format requires them to be encoded as hex — puhlen
– puhlen, Commented Sep 20, 2017 at 19:08

Dima · Accepted Answer · 2017-09-25 17:14:35Z

27

Equivalent, but a bit more efficient:

MessageDigest.getInstance("SHA-256")
  .digest("some string".getBytes("UTF-8"))
  .map("%02x".format(_)).mkString

edited Sep 25, 2017 at 17:14

answered Sep 20, 2017 at 21:46

Dima

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3 Comments

An Illusion Over a year ago

Hash code generated using your mehtod doesnt seem to be equivalent to what is generated using the method from previous answer: imgur.com/a/a3Gfv

Dima Over a year ago

Yeah, sorry about that. Fixed now.

Dima Over a year ago

@Regressor that's a Sting.format instruction. x means hexademical, 02 means two digits, padded with 0 if necessary. So, say, 10 (a in hex) is printed as "0a", and 255 (ff) is "ff"

Asherah · Accepted Answer · 2024-05-14 15:01:19Z

13

java.security.MessageDigest#digest gives a byte array.

scala> import java.security.MessageDigest
scala> import java.math.BigInteger

scala> MessageDigest.getInstance("SHA-256").digest("some string".getBytes("UTF-8"))
res1: Array[Byte] = Array(97, -48, 52, 71, 49, 2, -41, -38, -61, 5, -112, 39, 112, 71, 31, -43, 15, 76, 91, 38, -10, -125, 26, 86, -35, -112, -75, 24, 75, 60, 48, -4)

To create the hex, use String.format,

scala> val hash = String.format("%064x", new BigInteger(1, MessageDigest.getInstance("SHA-256").digest("some string".getBytes("UTF-8"))))
hash: String = 61d034473102d7dac305902770471fd50f4c5b26f6831a56dd90b5184b3c30fc

You can verify hash with command line tool in linux, unix

$ echo -n "some string" | openssl dgst -sha256
61d034473102d7dac305902770471fd50f4c5b26f6831a56dd90b5184b3c30fc

edited May 14, 2024 at 15:01

Asherah

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answered Sep 20, 2017 at 19:15

prayagupadhyay

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2 Comments

Gustek Over a year ago

Small bug here, string representation is missing leading 0's, for example string 39 will return b918943df0962bc7a1824c0555a389347b4febdc7cf9d1254406d80ce44e3f9 instead of 0b918943df0962bc7a1824c0555a389347b4febdc7cf9d1254406d80ce44e3f9

Alex Hall Over a year ago

Seems like you meant to use "%064x" instead of "%032x", that should solve the padding so you don't need padTo

Aaron_ab · Accepted Answer · 2019-03-06 10:04:58Z

1

Can use DatatypeConverter.printHexBinary.

Something like:

DatatypeConverter.printHexBinary(
  MessageDigest
    .getInstance(algorithm)
    .digest("some string").getBytes("UTF-8")))

answered Mar 6, 2019 at 10:04

Aaron_ab

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Comments

counter2015 · Accepted Answer · 2022-09-06 11:02:13Z

0

Since jdk 17, we can use java.util.HexFormat

import java.security.MessageDigest
import java.util.HexFormat

val bytes = MessageDigest.getInstance("SHA-256")
  .digest("any string".getBytes("UTF-8"))

val sha256 =  HexFormat.of().formatHex(bytes)
// 1e57a452a094728c291bc42bf2bc7eb8d9fd8844d1369da2bf728588b46c4e75

val another = HexFormat.ofDelimiter(":").withUpperCase().formatHex(bytes)
// 1E:57:A4:52:A0:94:72:8C:29:1B:C4:2B:F2:BC:7E:B8:D9:FD:88:44:D1:36:9D:A2:BF:72:85:88:B4:6C:4E:75

answered Sep 6, 2022 at 11:02

counter2015

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