i have a string like
a=b c=d e=f g=h i=j j=k
How to parse this string to get the value of j?
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3what did you done sor far for this?tanaydin– tanaydin2017-09-18 11:50:15 +00:00Commented Sep 18, 2017 at 11:50
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1Why "j"? What's unique about it? Is there a fixed pattern?Maroun– Maroun2017-09-18 11:55:46 +00:00Commented Sep 18, 2017 at 11:55
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How are you getting this string input?anubhava– anubhava2017-09-18 14:00:34 +00:00Commented Sep 18, 2017 at 14:00
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4 Answers
This will print anything followed by j= till upcoming space regardless of column number of j.
echo "a=b c=d e=f g=h i=j j=k" |grep -oP 'j=\K[^ ]+'
k
If you mean, the value of last column, which in this case is j=k:
echo "a=b c=d e=f g=h i=j j=k" |awk '{split($NF,a,"=");print a[2]}'
k
Note: Solution 1 is based on regex for the value of j, whereas solution 2 is for the last column's value. Its up to you to chose which one fits better to your requirement.
Or using gensub of awk:
echo "a=b c=d e=f g=h i=j j=k" |awk '{J=gensub(/.*j=([^ ]+).*/,"\\1","g");print J}'
k
or using gawk match function:
echo "a=b c=d e=f g=h i=j j=k" |awk '{match($0,/.*j=([^ ]+).*/,a);print a[1]}'
k
or using sed back refrencing:
echo "a=b c=d e=f g=h i=j j=k"|sed -r 's/.*j=([^ ]+).*/\1/'
k
Comments
With awk:
awk '{ for (i=1;i<=NF;i++) { split($i,arr,"=");if (arr[1]=="j") { print arr[2] } } }' <<< "a=b c=d e=f g=h i=j j=k"
Look through each space separated field and then further split the fields into an array (arr) delimited on =. If the first subscript of the array is j, print the second subscript.
Comments
There is lot of ways to do that in bash. The better depends on the strings pattern.
Assuming the pattern would always be key=value_without_whitespace key2=value2 ... a way could be:
echo "a=b c=d e=f g=h i=j j=k" | grep -P -o 'j=([^ ])' | cut -d '=' -f 2
Comments
Use source. pass semicolon separated string as file descriptor
source <(echo "a=b c=d e=f g=h i=j j=k" | tr ' ' ';')
echo $j
k
