Python: Getting the Index of a list

Question

I'm trying to create a program that will take input of a sentence and a word and check that sentence for the word and return the index of the beginning of the word i.e.

sentence = "random set of words" 
     word = "of"
     result = 9

This is what I tried

sentence = (input("Enter a sentence: "))
word = (input("Enter a Word: "))

result = sentence.split()

for x in sentence:
  if x == (word):
    boom = enumerate(word)
print(boom)

It should be, for x in result: so that you can get individual words each time the loop runs. — pvkcse
– pvkcse, Commented Sep 12, 2017 at 1:43

Asen · Accepted Answer · 2017-09-12 01:58:51Z

2

Just use index()

a = "aa bb cc"

b = "bb"

print a.index(b)

If the OP wants it to only count letters:

a = "aa bb cc"

b = "bb"

index_t = a.index(b)

real_index = index_t - a[:index_t].count(' ')

edited Sep 12, 2017 at 1:58

answered Sep 12, 2017 at 1:44

Asen

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2 Comments

Sam51 Over a year ago

This will also count the whitespaces as characters, so the original example returns 11, and I think the OP wants it to only count letters, so strip the whitespaces and this is best.

Asen Over a year ago

Some error will happen if use strip, like string "go fire of yeah", it will be "gofireofyeah", the index of "of" will be 2 not 7.

Sam51 · Accepted Answer · 2017-09-12 01:41:31Z

1

Assuming the word only appears once, I'd do it like this:

sentence = sentence.split(word)
sentence[0] = sentence[0].replace(" ","")
result = len(sentence[0])

answered Sep 12, 2017 at 1:41

Sam51

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