How to initialize complicated array JS?

Question

I use TypeScript for create array:

private menuItems: Menu[][];

After in loop I try to fill this like:

this.menuItems[role].push(this.menu[i]);

In result I want to get the following:

[1 : [{obj}, {obj}], 2: [{obj}, {obj}], 3: [{obj}, {obj}]]

What I do wrong?

Full code is:

public getMenuByRole(role: number): Menu[][] {
    for ( let i = 0; i < this.menu.length; i++ ) {
      if (this.menu[i].role === role && this.menu[i].avaliable) {
          this.getTranslateMenuItem(this.menu[i].title).subscribe((translation: string) => {
            this.menu[i].title = translation;
            this.menuItems[role].push(this.menu[i]);
          });
      }
    }
    return this.menuItems;
  }

Problem is that I try to add new objecti in array by custom key array, that is not exist

I tried also this:

const obj = {};
const arr = Array();

The in loop:

arr.push(this.menu[i]);
obj[role].push(arr);

please, show some relative code you have written for it and also error, if you are getting one. — Raghav Garg
– Raghav Garg, Commented Sep 9, 2017 at 19:43
This is full code. I initialize array [][], and tried to fill it — user3573738
– user3573738, Commented Sep 9, 2017 at 19:44
what does this.menu contains? Maybe you can show some sample data. — Raghav Garg
– Raghav Garg, Commented Sep 9, 2017 at 19:44
I guess, that it should be object of array like as: {1 : [{}. {}], 2: [{}, {}] } — user3573738
– user3573738, Commented Sep 9, 2017 at 19:46
Aside: I might invert your logic such that the menu item knows what roles it can be shown to. Each menu item could have children: menuItem[]. This way you can build your menu graph without a complex array. — AJ X.
– AJ X., Commented Sep 9, 2017 at 19:54

Carbosound1 · Accepted Answer · 2017-09-11 06:25:05Z

1

You just need to create an array inside an array to get a two dimensional array. I would use an object though. Hope this is what you are looking for

class A {
 private menu: [];

 constructor(){

 this.menu = new Array();
 for(let i = 0; i< 10; i++){
    let menuItem = new Array();
    menuItem.push(new B(i));
    menuItem.push(new B(i+1));
    this.menu.push(menuItem);
  }
  console.log(this.menu);
 }
}

class B {

 constructor(public x: int){
 }
}

new A();

https://jsfiddle.net/64r04pp2/

answered Sep 11, 2017 at 6:25

Carbosound1

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