VSCode Python Debugging Doesn't Honor Breakpoints When Using python.pythonPath

Question

With an empty workspace settings (settings.json), I can use the classic python launch configuration to debug my file. For example:

{
  "name": "Launch",
  "type": "python",
  "request": "launch",
  "stopOnEntry": true,
  "pythonPath": "${config:python.pythonPath}",
  "program": "${workspaceRoot}/someFile.py",
  "cwd": "${workspaceRoot}",
  "env": {},
  "envFile": "${workspaceRoot}/.env",
  "debugOptions": [
    "WaitOnAbnormalExit",
    "WaitOnNormalExit",
    "RedirectOutput"
  ]
}

Great. Stepping thru code works excellent (osx python 2.7).

I have a virtual environment created. I ran virtualenv <vname>. All of my source lives in the <vname> dir, along with the bin, lib, etc folders that virtualenv created.

Now, I have set "python.pythonPath": "${workspaceRoot}/bin/python" in my VSCode settings (VSCode v1.16.0). The python executes, but debugger points are not honored.

What'd I do wrong? Thx!

Omrum Cetin · Accepted Answer · 2019-07-05 13:34:16Z

1

Add below setting in launch.json file

"justMyCode": false,

answered Jul 5, 2019 at 13:34

Omrum Cetin

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1 Comment

DiFox Over a year ago

My god, thank you a lot. I spent more than 2 hours to find a problem, and finally it works.

tuannv256 · Accepted Answer · 2017-09-08 02:42:55Z

0

Python path should be set:

"python.pythonPath": ${workspaceRoot}/<vname>/bin/python"

with <vname> is virtual environment directory, created by using virtualenv <vname>

edited Sep 8, 2017 at 2:42

answered Sep 8, 2017 at 2:29

tuannv256

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1 Comment

cdaringe Over a year ago

as noted above, i moved my project files into <vname>. the code executes fine, it just doesn't break. are you suggesting that my convention is not permitted?

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