REGEX in python2.7

Question

I cannot seem to figure out how to write a regex to match on if all match in python:

{'ERROR_CODE': 500}
{'ERROR_CODE': 404}
{'ERROR_CODE': 501}
{'ERROR_CODE': 409}

I need the regex to match {'ERROR_CODE': first, which can be followed be either 5XX OR 4XX, and ending with }

i am able to specify and get it to work, how to make it match on the entire range 400-499 or 500-599.

// python snippet
err_pattern = re.compile("{\'ERROR_CODE\': 500}|{\'ERROR_CODE\': 404}")
if all(err_pattern.match(str(values)) for values in self.set.values()):
    output.append('All are 4XX and 5XX')

Any help would be highly appreciated.

markdly · Accepted Answer · 2017-09-07 04:49:09Z

1

This is one way you could do it:

import re
values = ["{'ERROR_CODE': 500}",
          "{'ERROR_CODE': 404}",
          "{'ERROR_CODE': 501}",
          "{'ERROR_CODE': 409}]"]

err_pattern = re.compile("\{\'ERROR_CODE\': [45]\d{2}\}")

for value in values:
    if err_pattern.match(value):
        output = "All are 4XX and 5XX"
    else:
        output = "Some values are not error codes"
        break

print output
# All are 4XX and 5XX

answered Sep 7, 2017 at 4:49

markdly

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Comments

Taku · Accepted Answer · 2017-09-07 04:52:37Z

1

how to make it match on the entire range 400-499 or 500-599.

The 4 and 5 are constant, and the second and third number are all 0-9 digits. Therefore you can make a regex like this:

re.compile(r"\{'ERROR_CODE': [45]\d{2}\}")

Which matches number starts with 4 or 5, followed by 2 digits.

edited Sep 7, 2017 at 4:52

answered Sep 7, 2017 at 4:40

Taku

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