JSON Multiple Array to show list

Question

Array
(
    [0] => Job
    [1] => 
    [2] => Array
        (
            [0] => stdClass Object
                (
                    [AppDataId] => 16368
                    [JobTitle] => Sigma Six Black Belt/Lean Administration Consultant
                    [Abstract] => Sigma Six Black Belt/Lean Administration Consultan ... - open
                )

            [1] => stdClass Object
                (
                    [AppDataId] => 16367
                    [JobTitle] => General Manager (Power Generation)
                    [Abstract] => General Manager (Power Generation) - Botswana
                )

            [2] => stdClass Object
                (
                    [AppDataId] => 16366
                    [JobTitle] => Resident  Engineer - Mpumalanga
                    [Abstract] => Resident  Engineer - Mpumalanga - Mpumalanga
                )

        )

    [3] => 
)

I need to get this into a PHP array and list all the JobTitle's or any other field

I've done this but I cannot figure out how to access only JobTitle firstly, and then secondly list all of them. $json_url is the actual url of the json file that outputs the info above.

$json1 = file_get_contents($json_url);
$array = json_decode($json1);
echo "<pre>";
print_r($array);
echo "</pre>";

$strJob=array();
foreach ($array as $value) { 
    $strJob[2][1]=$value->JobTitle;
}
echo '<br/>';
print_r($strJob);
echo '<br/>';

$strJob[2][1]=$value->JobTitle; - now how is that supposed to make any sense? The only entry you are creating in your array $strJob is the one under the keys [2][1], and you are overwriting that one in every loop iteration. — C3roe
– C3roe, Commented Aug 22, 2017 at 13:41
You want to loop over $array[2] to begin with, because only that contains the sub-structure of objects to loop over. And then you simply add the job title as a new entry into your array, $strJob[]=$value->JobTitle; — C3roe
– C3roe, Commented Aug 22, 2017 at 13:43
Same way as you are trying to loop over $array right now …? — C3roe
– C3roe, Commented Aug 22, 2017 at 14:03

Sagar Patil · Accepted Answer · 2017-08-22 13:54:46Z

1

You should use below syntax:

if(isset($array[2])) {
  foreach ($array[2] as $value) {
     echo 'JobTitle ->' . $value->JobTitle . '<br/>';
     echo 'AppDataId ->' . $value->AppDataId. '<br/>';
  }
}

answered Aug 22, 2017 at 13:54

Sagar Patil

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1 Comment

Natie Rautenbach Over a year ago

Thank you, that is what I was looking for.

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