Getting error while doing subprocess call using Python and Django

Question

I am getting some error while running the .sh script using Python and Django. The errors are given below.

Traceback (most recent call last):
  File "cell.py", line 3, in <module>
    subprocess.call(shlex.split('./test.sh param1 param2'))
  File "/usr/lib/python2.7/subprocess.py", line 522, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/usr/lib/python2.7/subprocess.py", line 710, in __init__
    errread, errwrite)
  File "/usr/lib/python2.7/subprocess.py", line 1327, in _execute_child
    raise child_exception
OSError: [Errno 13] Permission denied

I am explaining my code below.

cell.py:

  import subprocess
import shlex
param1='Reactor1'
param2='Running'
subprocess.call(shlex.split('bash test.sh',param1,param2))

test.sh:

#!/bin/sh
echo $1
echo $2
exit 0

While I was running the file I am getting the above error. Please help me to resolve this error.

I just created the file and saved inside the same project folder. — user5443928
– user5443928, Commented Aug 16, 2017 at 11:17
go check it then... alternatively try bash test.sh param1 param2 — Nils Werner
– Nils Werner, Commented Aug 16, 2017 at 11:17
@NilsWerner : Ok I did as per you and also error gone but the echo message is not coming. — user5443928
– user5443928, Commented Aug 16, 2017 at 11:33

Sanket · Accepted Answer · 2017-08-16 12:02:36Z

1

Replace your

subprocess.call(shlex.split('bash test.sh',param1,param2))

To

subprocess.call(shlex.split('bash test1.sh %s %s'%(param1,param2)))

or

subprocess.call(['bash', 'test1.sh', param1, param2])

edited Aug 16, 2017 at 12:02

answered Aug 16, 2017 at 11:39

Sanket

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2 Comments

Sanket Over a year ago

@subhra you are passing parameter but not formatted correctly, that was the error

Nils Werner Over a year ago

why create a string only to split it again later? Just use subprocess.call(['bash', 'test1.sh', param1, param2]) instead

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