I'm trying to locate element by
element=driver.find_element_by_partial_link_text("text")
in Python selenium and the element does not always exist. Is there a quick line to check if it exists and get NULL or FALSE in place of the error message when it doesn't exist?
You can implement try/except block as below to check whether element present or not:
from selenium.common.exceptions import NoSuchElementException
try:
element=driver.find_element_by_partial_link_text("text")
except NoSuchElementException:
print("No element found")
or check the same with one of find_elements_...() methods. It should return you empty list or list of elements matched by passed selector, but no exception in case no elements found:
elements=driver.find_elements_by_partial_link_text("text")
if not elements:
print("No element found")
else:
element = elements[0]
Sometimes the element does not appear at once, for this case we need to use explicit wait:
browser = webdriver.Chrome()
wait = WebDriverWait(browser, 5)
def is_element_exist(text):
try:
wait.until(EC.presence_of_element_located((By.PARTIAL_LINK_TEXT, text)))
except TimeoutException:
return False
Solution without try/ except:
def is_element_exist(text):
elements = wait.until(EC.presence_of_all_elements_located((By.PARTIAL_LINK_TEXT, text)))
return None if elements else False
How explicit wait works you can read here.
Imports:
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
quick statement to check? Selenium doesn't supportsstatement. You have to write a line/block of code.driver.find_element_by_partial_link_text("text")is quick enough way to check if element exists... Can you be more explicit about what you want your code to do?