Java URL encoding with url encode parameters

Question

How to encode in Java this String

http://demo.pl/sample?id=tests%trg=https%3A%2F%2Fwww.google.com%sample.html%3Fwmc%3DAFF48+_LS.%23%7NUMBER_ID%7D_%23%7NUMBER_ID%7D..

java.net.URLEncoder encode this String like this:

http%3A%2F%2Fdemo.pl%2Fsample%3Fid%3Dtests%25trg%3Dhttps%253A%252F%252Fwww.google.com%25sample.html%253Fwmc%253DAFF48%2B_LS.%2523%257NUMBER_ID%257D_%2523%257NUMBER_ID%257D..

I expect this result:

http%3A%2F%2Fdemo.pl%2Fsample%3Fid%3Dtests%25trg%3Dhttps%3A%2F%2Fwww.google.com%sample.html%3Fwmc%3DAFF48+_LS.%23%7NUMBER_ID%7D_%23%7NUMBER_ID%7D..

I do not want to encode encoded part of String. Needs a universal algorithm. String is not always encoded fragmentarily — Wait
– Wait, Commented Jun 29, 2017 at 13:57

Slava Vedenin · Accepted Answer · 2017-06-29 14:03:11Z

2

I think following code can help you:

String s = "http://demo.pl/sample?id=tests%trg=https%3A%2F%2Fwww.google.com%sample.html%3Fwmc%3DAFF48+_LS.%23%7NUMBER_ID%7D_%23%7NUMBER_ID%7D";
int i = s.indexOf("%");
String result1 = URLEncoder.encode(s.substring(0, i)) + "%25" + s.substring(i + 1);
System.out.println(result1); // print http%3A%2F%2Fdemo.pl%2Fsample%3Fid%3Dtests%25trg=https%3A%2F%2Fwww.google.com%sample.html%3Fwmc%3DAFF48+_LS.%23%7NUMBER_ID%7D_%23%7NUMBER_ID%7D

I do not want to encode encoded part of String. Needs a universal algorithm. String is not always encoded fragmentarily

I think universal algorithm is impossible in that case, what you can do that find encoded part manually and not encoded it again (see code above).

edited Jun 29, 2017 at 14:03

answered Jun 29, 2017 at 13:57

Slava Vedenin

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