Extract substring with Regex on Python 3

Question

I'm trying to extract a substring with Regex,

Here is my script:

import re
_text = "sdiskpart(device='D:\\', mountpoint='D:\\', fstype='FAT32', opts='rw,fixed')"
print(re.findall("device=(\\'.*\\')", _text))

I'm trying to get the value of device, in this string it's "D:\"

as u can see I tried "device=(\'.*\')" with REgex and it returned:

["'D:\', mountpoint='D:\', fstype='FAT32', opts='rw,fixed'"]

I'm not professional on REgex, How can I force it to take D:\ and print it out ?

>>> print(re.findall("device=(\\'[A-Z]:\\\\')", _text)) ["'D:\\'"] — Anoop Toffy
– Anoop Toffy, Commented Jun 22, 2017 at 4:02

Chris · Accepted Answer · 2017-06-22 04:08:13Z

4

You can use non-eager regexp

import re

print( re.findall("device='(.*?)'", _text))

notice that the .*? means non-eager so it will take the least chars until the next ' ...

edited Jun 22, 2017 at 4:08

Chris

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answered Jun 22, 2017 at 4:06

Yoav Glazner

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2 Comments

njzk2 Over a year ago

what is the difference in performance compared to using ([^']) (character class of inverse-quote, i.e. all characters but quote) ?

Yoav Glazner Over a year ago

@njzk2 - running timeit resulted in that ".*?" is a bit slower. both does not require backtracking though so I guess they are somewhat in the same order of complexity.

Anoop Toffy · Accepted Answer · 2017-06-22 04:05:49Z

2

REFER https://docs.python.org/3/library/re.html

>>> print(re.findall("device=(\\'[A-Z]:\\\\')", _text))
["'D:\\'"]

You might have to replace * with [A-Z]. I think the drive letter are in caps always else use[A-Za-z]

answered Jun 22, 2017 at 4:05

Anoop Toffy

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1 Comment

DarkSuniuM Over a year ago

what if there is no :\\\\ after [A-Z]?

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