is it possible to sort a sorted array based on another object in javascript?

Question

I am sorting this type of array by genre:

const bands = [ 
  { genre: 'Rap', band: 'Migos', albums: 2},
  { genre: 'Pop', band: 'Coldplay', albums: 4, awards: 10},
  { genre: 'Pop', band: 'xxx', albums: 4, awards: 11},
  { genre: 'Pop', band: 'yyyy', albums: 4, awards: 12},
  { genre: 'Rock', band: 'Breaking zzzz', albums: 1}
  { genre: 'Rock', band: 'Breaking Benjamins', albums: 1}
];

With this:

function compare(a, b) {
  // Use toUpperCase() to ignore character casing
  const genreA = a.genre.toUpperCase();
  const genreB = b.genre.toUpperCase();

  let comparison = 0;
  if (genreA > genreB) {
    comparison = 1;
  } else if (genreA < genreB) {
    comparison = -1;
  }
  return comparison;
}

As describe here But after sorting by genre, I also want to sort it by number of albums.Is it possible? TIA

How is the title related to the question? "sort based on another object" vs. "sort by multiple properties" — Andreas
– Andreas, Commented May 29, 2017 at 14:37
Possible duplicate of Javascript, how do you sort an array on multiple columns? — Andreas
– Andreas, Commented May 29, 2017 at 14:41
That's I what I really meant but I just find the right words earlier. Thank you so much. — silent_coder14
– silent_coder14, Commented May 29, 2017 at 14:46

Jonas Wilms · Accepted Answer · 2017-05-29 14:37:28Z

1

function compare(a, b) {
// Use toUpperCase() to ignore character casing
const genreA = a.genre.toUpperCase();
const genreB = b.genre.toUpperCase();

return genreA.localeCompare(genreB) || a.albums-
b.albums;
}

I shortified your code to genreA.localeCompare(genreB). If it is 0, the genres are equal, and we'll therefore compare by the number of albums.

This if 0 take ... instead is provided by the OR operator...

answered May 29, 2017 at 14:37

Jonas Wilms

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Comments

Rick · Accepted Answer · 2017-05-29 17:18:18Z

Sure, after you are done doing whatever you need to do with the first array. Assuming you don't want to modify your first array, you can make a copy by using slice. Then you can sort by album number. Let me know if this helps

const bands = [{
    genre: 'Rap',
    band: 'Migos',
    albums: 2
  },
  {
    genre: 'Pop',
    band: 'Coldplay',
    albums: 4,
    awards: 10
  },
  {
    genre: 'Pop',
    band: 'xxx',
    albums: 4,
    awards: 11
  },
  {
    genre: 'Pop',
    band: 'yyyy',
    albums: 4,
    awards: 12
  },
  {
    genre: 'Rock',
    band: 'Breaking zzzz',
    albums: 1
  },
  {
    genre: 'Rock',
    band: 'Breaking Benjamins',
    albums: 1
  }
];


var sortedAlbumNumber = bands.slice();

sortedAlbumNumber.sort((a, b) => a['albums'] - b['albums']);

console.log(sortedAlbumNumber);

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