I'm trying to check for an empty string array like this:
var array = ['',''];
//Other code
if (array == ['',''])
//Do stuff
and I've found that
['',''] == ['','']
returns false. Why is that? What method should I use to check for an empty string array? Is there a way where I don't have to check each individual item?
Beside the proposed using of Array#toString method, I suggest to use Array#join with an empty string as separator and then test the result. The advantage is, it works for an arbitrary count of elements inside of the array.
var bool = array.join('') ? 'not all empty string' : 'all empty string';
join.['', ''] == ['', ''] returns false because in JavaScript arrays are objects, and objects in JavaScript have reference semantics. Comparing objects to each other actually compares their reference IDs, which will be different for different references. So, even though both sides of == are the "same" array, they are different references.
If you want to check that an array only contains empty strings, use Array.prototype.every as in the following:
myArray = ['']
console.log(myArray.every(el => el === '')) // true
myArray = []
console.log(myArray.every(el => el === '')) // true
myArray = ['test']
console.log(myArray.every(el => el === '')) // falseIf you are in an environment without ES6 support, you can swap the el => el === '' for function(el) { return el === '' }.
You can do this:
var arr = ["","", ""].reduce(function (a, b) {
return a + b;
});
if(arr == "") {
console.log('Array is empty');
}
This should also work:
var arr = [""];
console.log(String.valueOf(arr[0]) === String.valueOf(''));
Based on the answer from Nina above this should also work!
let arr1 = ['']
const bool1 = !!arr1.join(''); // false
console.log(bool1)
let arr2 = ['String']
const bool2 = !!arr2.join(''); // true
console.log(bool2)
arraycontains only empty strings