How to check if String contains all Strings from Array.
My current code:
String word = "abc";
String[] keywords = {"a", "d"};
for(int i = 0; i < keywords.length; i++){
if(word.contains(keywords[i])){
System.out.println("Yes");
}else{
System.out.println("No");
}
}
The code would look much more nicer if you wrap it into a separate method:
public static boolean containsAllWords(String word, String ...keywords) {
for (String k : keywords)
if (!word.contains(k)) return false;
return true;
}
If you are using Java 8+, you could use a Stream and test if all of the elements match your criteria with one line. Like,
if (Stream.of(keywords).allMatch(word::contains)) {
System.out.println("Yes");
} else {
System.out.println("No");
}
In earlier versions, or if you want to understand what the above is doing, it might look something like
boolean allMatch = true;
for (String kw : keywords) { // <-- for each kw in keywords
if (!word.contains(kw)) { // <-- if "word" doesn't contain kw
allMatch = false; // <-- set allMatch to false
break; // <-- stop checking
}
}
if (allMatch) {
System.out.println("Yes");
} else {
System.out.println("No");
}
Use a boolean variable that will tell you if every keyword is matched. Set it to true as default value. Then check every keword: if any one is not contained in your word, stop searching and set your variable to false.
boolean containsAll = true;
for (String keyword : keywords){
if (!word.contains(keyword)){
containsAll = false;
break;
}
}
Note this solution work only if your keywords contain one char, there are many answers already mentioned if your keywords contain more then one char.
With one line :
boolean contain = Arrays.asList(word.split("")).containsAll(Arrays.asList(keywords));
The idea is :
String word = "abc";
String[] split = word.split("");
Split your String to get an array of chars split = {a, b, c}
String[] keywords = {"a", "b"};
Check if your array1 contain all the element of the second array2 using containsAll
boolean contain = Arrays.asList(split).containsAll(Arrays.asList(keywords));
Either use StringUtils (org.apache.commons.lang.StringUtils). It will return the index of the first occurrence of keywords or -1 if it is not there.
StringUtils.indexOfAny(word, keywords);
Or you can use Arrays which will return the boolean value.
Arrays.asList(word).contains(keywords)
A better code would be:
for(String s: keywords){
if(word.contains(s)){
System.out.println("Yes");
}else{
System.out.println("No");
}
}
Simply use a counter:
String word = "abc";
String[] keywords = {"a", "d"};
int counter = 0;
for(int i = 0; i < keywords.length; i++){
if(word.contains(keywords[i])){
counter++;
}
}
if(counter == keywords.length){
System.out.println("Yes");
}else{
System.out.println("No");
}
If the counter equals the keywords length, it means that all elements are contained. With this solution you will also be able to find out how many keywords are matched by the word.
