1

First of all I am new to JavaScript.

I would like to insert variables into this type of array dynamically that containing latitude and longitude. Hoping for helps...

var locations = [
  [ test, test1],
  [ -33.923036, 151.259052],
  [ -34.028249, 151.157507],
  [ -33.80010128657071, 151.28747820854187],
  [-33.950198, 151.259302 ]
]; 

var test = -33.923036; var test1 = 151.259052;

Thanks in advance.

4
  • What is the issue ? What is console.log(locations) ? Commented Apr 7, 2017 at 6:09
  • locations.push(test); Commented Apr 7, 2017 at 6:10
  • I tried with array splice but i didnt get to know how to add array into another array? Commented Apr 7, 2017 at 6:11
  • locations.push([test, test1]). Or with .splice() (since you tried to use that, though .push() is a much better option): locations.splice(someIndex, 0, [test, test1]). Commented Apr 7, 2017 at 6:11

7 Answers 7

1

Try this -

You have to use push method to insert an object to array.

var test = -33.923036; var test1 = 151.259052;

var locations = [
 
  [ -33.923036, 151.259052],
  [ -34.028249, 151.157507],
  [ -33.80010128657071, 151.28747820854187],
  [-33.950198, 151.259302 ]
]; 

locations.push([test, test1])

console.log(locations)

Sign up to request clarification or add additional context in comments.

2 Comments

You have to use push method to insert - You don't have to use that method: .push() is just one of several ways to add an element to an array, and note that it doesn't "insert" so much as "append".
Yes Indeed. there are always many options. Its just what came to my mind when I read the question :) Thanks anyways
0

Try this locations.push([variable_name_1,variable_name_2])

Comments

0

You have to declare test and test1 before locations:

var test = 1, test1 = 2;

var locations = [
  [ test, test1],
  [ -33.923036, 151.259052],
  [ -34.028249, 151.157507],
  [ -33.80010128657071, 151.28747820854187],
  [-33.950198, 151.259302 ]
]; 

console.log(locations);

Comments

0

You can use push method to add new element in an array.

var newValues = [test,test1];
locations.push(newValues);

2 Comments

can we add both test and test1 together? using push
Updated the answer
0
var test = -33.923036; var test1 = 151.259052;
var locations = [
 [ test, test1],
 [ -33.923036, 151.259052],
 [ -34.028249, 151.157507],
 [ -33.80010128657071, 151.28747820854187],
 [-33.950198, 151.259302 ]
]; 

or

var locations = [
 [ -33.923036, 151.259052],
 [ -34.028249, 151.157507],
 [ -33.80010128657071, 151.28747820854187],
 [-33.950198, 151.259302 ]
]; 

locations.push([-33.923036,151.259052])

or

var test = -33.923036; var test1 = 151.259052;

locations.push([test,test1])
console.log(locations);

1 Comment

[ `${test}`, `${test1}`] makes no sense: why would you convert the values to strings when all of the other array items are numbers?
0

First declare your variable

var test = -33.923036; var test1 = 151.259052;

then perform push

locations.push([test,test1]);

Comments

0

For a dynamic insert of some values, you could wrap it in the array, you need and access as before.

If you change the value inside of loc, you get the actual value in loations as well, because you have a reference between loc and locations[0].

As long as you do not overwrite locations[0], with a new array or primitive value, you could access the actual value of loc.

var loc = [
        -33.923036,
        151.259052
    ],
    locations = [
        loc,
        [-33.923036, 151.259052],
        [-34.028249, 151.157507],
        [-33.80010128657071, 151.28747820854187],
        [-33.950198, 151.259302 ]
    ]; 

console.log(locations[0][0]); // -33.923036
loc[0] = 42;
console.log(locations[0][0]); // 42
locations[0][0] = -10;
console.log(locations[0][0]); // -10
console.log(loc);             // [-10,  151.259052]

1 Comment

Thanks for the answer.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.