Simple way to send an html/text email using sendgrid & python?

Question

I'm trying to use sendgrid to send email from my Python application.

It's sending fine using the mail helper and the following syntax:

sgmessage = mail.Mail(from_email, message.subject, to_email, content)
sg.client.mail.send.post(request_body=sgmessage.get())

But I can't find the way to send an email which has a multipart/alternative content type with text & html versions?

I've tried things like this:

sgmessage = mail.Mail(from_email, message.subject, to_email)
sgmessage.add_content(content)
sgmessage.add_content(htmlcontent)

But that gives me Bad Request when I try to send.

Could someone point me to the documentation or other tip for achieving this?

Also attachments -- I can't find docs for that handy mail helper which would help me add attachments ability to my code.

Sachin · Accepted Answer · 2018-10-07 12:13:42Z

12

Mail Helper Source https://github.com/sendgrid/sendgrid-python/blob/master/sendgrid/helpers/mail/mail.py

mail_html = Content(type_='text/html', value='<h1>Test Mail</h1><p>This is a test email message.</p>')
mail_txt = Content(type_='text/plain', value='This is a test email message.')
mail = Mail(mail_from, mail_subject, mail_to, mail_html)
mail.add_content(mail_txt)
response = sg.client.mail.send.post(request_body=mail.get())

The sample links are still 404's.

answered Oct 7, 2018 at 12:13

Sachin

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Comments

jacobmovingfwd · Accepted Answer · 2017-04-05 19:51:42Z

0

Have you looked at the SendGrid Python Library? The basic example only shows one content type, but the "kitchen sink" example shows setting both contents.

answered Apr 5, 2017 at 19:51

jacobmovingfwd

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2 Comments

Ramtin Over a year ago

Look at this link . At the time of writing, you need to look at the line of 31, in the type method.

jacobmovingfwd Over a year ago

Here's the link I got while I'm not logged in, so should hopefully stay good: github.com/sendgrid/sendgrid-python/blob/master/examples/…

Vishal Sinha · Accepted Answer · 2021-02-15 10:49:14Z

import os

from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail


def send_email(emails, notification_text, subject):
    """Send Emails

    Send email to the mail ids

    :param emails: emails of the user
    :type emails: list
    :param notification_text: notification text
    :type notification_text: str
    :param request_link: link to the requet
    :type request_link: str
    :param subject: subject of the email
    :type subject: str

    :rtype: str
    """
    html_content = '<strong>' + notification_text + '</strong>'
    emails = emails
    message = Mail(
        from_email='yourSendGridVerifiedEmail',
        to_emails=emails,
        subject=subject,
        html_content=html_content)
    try:
        sg = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
        sg.send(message)
        return "Email Sent"
    except Exception as e:
        return e.message

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