You can use the Serialize method to generate this xml from the model it self.
public string SerializeXml<T>(T config)
{
XmlSerializer xsSubmit = new XmlSerializer(typeof(T));
string xml = "";
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = false;
using (var sww = new StringWriter())
{
using (XmlWriter writer = XmlWriter.Create(sww, settings))
{
xsSubmit.Serialize(writer, config);
xml = sww.ToString();
}
}
return xml;
}
This will return XML string , you need the model which is similar to your required XML.
This is what i have created as model from your XML that you can change as per your requiment.
[XmlRoot(ElementName = "affdatalist")]
public class Affdatalist
{
[XmlElement(ElementName = "object1")]
public string Object1 { get; set; }
[XmlElement(ElementName = "object2")]
public string Object2 { get; set; }
[XmlElement(ElementName = "object3")]
public string Object3 { get; set; }
}
[XmlRoot(ElementName = "personData")]
public class PersonData
{
[XmlElement(ElementName = "affdatalist")]
public Affdatalist Affdatalist { get; set; }
[XmlElement(ElementName = "anotherObject1")]
public string AnotherObject1 { get; set; }
[XmlElement(ElementName = "anotherObject2")]
public string AnotherObject2 { get; set; }
}
[XmlRoot(ElementName = "personDatas")]
public class PersonDatas
{
[XmlElement(ElementName = "personData")]
public PersonData PersonData { get; set; }
}
You can use as sample below
PersonDatas data = new PersonDatas();
var xml = this.SerializeXml<PersonDatas>(data); // your model with data