For each instance of array-item in string

Question

I am trying to check for each instance of all array-items in a string. Example;

var string = "aa bb ccc";
var array = ["a", "b", "c"];

This should execute my code 7 times - once for each instance of any array-item being in the string. This is quite hard to explain, but I hope the example is enough.

Another explained-code example;

$.each(ArrayItem in string) {
    //execute code
}

I cannot get my head around this one, and haven't yet found anything that remotely works the way I want it to.

Edit

I want to use this to add a price for each letter - say "a,b,c,d,e,f,g" costs $1, while the rest costs $2 - I would need to check for each instance of the array-items above in my string, and calculate the price.

Did you try looking at REGEX? That would be 1000 times faster than what you are trying to do. — Akshay Khandelwal
– Akshay Khandelwal, Commented Mar 16, 2017 at 12:49
Yes, @Weedoze, the string is the input field and the array contains the items I want to check for. — Albert MN.
– Albert MN., Commented Mar 16, 2017 at 12:51

dfsq · Accepted Answer · 2017-03-16 12:57:27Z

2

You can use while+exec inside of for-loop over array items:

var string = "aa bb ass ccc ass"
var array = ["ass", "b", "c"]

var m

array.forEach(function(item) {
  var reg = RegExp(item, 'g')
  while ((m = reg.exec(string)) !== null) {
    console.log('match', m[0])
  }
})

answered Mar 16, 2017 at 12:57

dfsq

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3 Comments

kind user Over a year ago

Yep it's much better indeed. +1

evolutionxbox Over a year ago

What if you had a in the array as well?

dfsq Over a year ago

@evolutionxbox Then a from array will also be counted in ass from string. It's not clear what is the behavior OP expects in such case.

kind user · Accepted Answer · 2017-03-16 12:51:39Z

1

Split your string using spread operator and iterate over it to check if array contains any of the elements from that array.

var string = "aa bb ccc";
var array = ["a", "b", "c"];

[...string].forEach(v => array.some(function(c){
  if (c == v) {
    console.log('code executed');
  }
}));

answered Mar 16, 2017 at 12:51

kind user

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7 Comments

Rajesh Dixit Over a year ago

You can also try v=>array.includes(v) && process(v)

dfsq Over a year ago

Nope, not reliable. You assumed that string consists of charactes, but OP meant "strings".

kind user Over a year ago

@dfsq Can you provide me some counter example?

dfsq Over a year ago

For example: var string = "ass bb ccc"; var array = ["ass", "b", "c"]; there should be 6 code invocations, but your version will yield only 5 because ass will not be found.

kind user Over a year ago

@dfsq Hold on will look at it.

|

DeebashVFX · Accepted Answer · 2017-03-16 12:56:41Z

0

This function will do your work

    function checkString(a){
    for(i=0;i<a.length;i++)
        {  
          if(a[i]!==" "){
            if (yourArray.indexOf(a[i]) > -1) {
                //this line executes 7 times if the string a has 7 characters;
            } 
            }
        }

    }

answered Mar 16, 2017 at 12:56

DeebashVFX

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Comments

ibrahim mahrir · Accepted Answer · 2017-03-16 12:59:55Z

0

You have to split the string by ' ' to get an array of substrings, and then use forEach or $.each to loop throught them like:

Spliting:

var strings = string.split(' ');

or more effectivelly:

var strings = string.trim()         // remove sorrounding spaces
                    .split(/\s+/);  // split by any number of spaces

Looping using forEach:

strings.forEach(function(str) {
    // use str
});

Looping using $.each:

$.each(strings, function(i, str) {
    // use str
});

edited Mar 16, 2017 at 12:59

answered Mar 16, 2017 at 12:53

ibrahim mahrir

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Comments

Vitalii Andrusishyn · Accepted Answer · 2017-03-16 13:03:37Z

0

Use split method with " " parameter. https://www.w3schools.com/jsref/jsref_split.asp

var string = "aa bb ccc",
    array = string.split(" ");

Or you can also used lodash: https://lodash.com/docs/4.17.4#split

answered Mar 16, 2017 at 13:03

Vitalii Andrusishyn

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Comments

Nina Scholz · Accepted Answer · 2017-03-16 13:19:54Z

0

You could use an object and count the appearances of the letters. Later, you could separate by different priced values.

var string = "aa bb ccc xyz",
    array = ["a", "b", "c"],
    count = Object.create(null);

string.split('').forEach(function (a) {
    if (a !== ' ') {
        count[a] = (count[a] || 0) + 1;
    }
});

Object.keys(count).forEach(function (k) {
    if (array.indexOf(k) !== -1) {
        console.log('found ' + k + ' of array: ' + count[k] + ' times');
    } else {
        console.log('found ' + k + ': ' + count[k] + ' times');
    }
});

edited Mar 16, 2017 at 13:19

answered Mar 16, 2017 at 12:58

Nina Scholz

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7 Comments

dfsq Over a year ago

I don't think you are answering what OP asked.

Nina Scholz Over a year ago

could be, who knows.

Albert MN. Over a year ago

No, and the code snippet also only output one console log.

Nina Scholz Over a year ago

@iversen, please add some more examples and the wanted output.

Albert MN. Over a year ago

Gotcha, @NinaScholz adding them now

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