python can't parse json string

Question

I tried to parse json data but it didn't work, json parser return a strong not a dictionary!! Here the code:

import urllib2
from BeautifulSoup import BeautifulSoup
import json
html = urllib2.urlopen("http://www.imdb.com//name/nm0425005/mediaviewer/rm244453632?ref_=nmmi_mi_all_sf_49").read()
soup = BeautifulSoup(html)
script = soup.find('script', {'id': 'imageJson'})
json_data = ''.join(map(str, script.contents))
json_data = json.dumps(json_data.strip(' \t\n\r'))
data = json.loads(json_data)
print data['mediaViewerModel']

yes I printed the json data before pass it to json module, yet it looks alright — Tyranitar
– Tyranitar, Commented Feb 17, 2017 at 19:48

Randy · Accepted Answer · 2017-02-17 19:38:28Z

1

json_data = ''.join(map(str, script.contents))
>>> json_data = json.dumps(json_data.strip(' \t\n\r'))
data = json.loads(json_data)

The marked line is the problem. json_data is currently a string encoding a dictionary, and when you call json.dumps, it will then be a string encoding a string encoding a dictionary, and your last line just undoes one instance. What is it that you're actually trying to do with the marked line?

answered Feb 17, 2017 at 19:38

Randy

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2 Comments

Tyranitar Over a year ago

I tried only loads to load the function but it didn't works, I got this error: ValueError: Expecting , delimiter: line 2 column 515 (char 515) I add dumps I thought it will fix the syntax of json

Randy Over a year ago

That's telling you that what you're trying to parse isn't valid JSON. Since you're scraping it from a site, you're probably getting something back without proper escaping or something vs. what you'd get from an API.

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