How to execute multiple commands on remote server and get the output?

Question

I have a requirement to execute some commands on remote machine and i have written script like this on my local machine.

Basically i'm getting docker images on my local machine and want to check whether those images are existing in remote server or not.

I need to get non existing docker images (remote server) to my local machine. For that i have used below mentioned code, but it didn't work for me.

#!/bin/sh
declare array=$(docker images)
sshpass -p 'password' ssh -t [email protected] << EOF
declare List=""
while read -r line; do
  if [ -z $(docker images -q $line) ]; then
    List="$List $line"
  else
    continue
  fi
done <<< "$array"
EOF

I want List variable to be in my local machine.

Can anyone help me on this issue?
Your help is much appreciated.
Best Regards.

if i do echo it prints on the screen. how can i capture that into some variable in my local machine to use it further. — kala
– kala, Commented Feb 7, 2017 at 9:28
sshpass -p 'password' ssh -t [email protected] >local_file << EOF ... — Kirill Bulygin
– Kirill Bulygin, Commented Feb 7, 2017 at 9:29

tripleee · Accepted Answer · 2017-02-07 10:03:30Z

1

Nothing you do in the remote shell will be present in your local shell once the remote shell exits. What you can do is have the remote shell print output and capture that.

By the by, you can't use arrays in a /bin/sh script, but we don't actually need arrays here.

#!/bin/sh
docker images |
sshpass -p 'password' ssh -t [email protected] '
  while read -r line; do
    # Suction: docker images -q image should return nonzero exit status
    # if the named image is missing.  We work around that by grepping
    # for whether there is any output at all.
    docker images -q "$line" | grep -q . || echo "$line"
  done'

This just prints out the result; capture that into a variable or redirect it to a file in order to do something more with it, or just pipe it into another local while read -r loop.

If you refactor this so that e.g. the authentication details are parametrized, you can run it against a number of hosts. You could save it as an executable script so you can call it from any other tool, or as a function if you just need it in a limited context.

missing () {
    docker images -q |
    "$@" 'while read -r line; do          
        docker images -q "$line" | grep -q . || echo "$line"
    done'
}

Now you can call it for one or more hosts:

missing sshpass -p 'password' ssh -t [email protected] |
xargs -r -n 1 docker pull

edited Feb 7, 2017 at 10:03

answered Feb 7, 2017 at 9:30

tripleee

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6 Comments

tripleee Over a year ago

stackoverflow.com/questions/5725296/… discusses the differences between sh and bash.

tripleee Over a year ago

Parametrizing the entire ssh command line is perhaps a somewhat dubious design, but at least it should inspire you to explore how this can be made modular and reusable.

kala Over a year ago

its working really fine. but i am executing this script in jenkins which says sshapss command not found and we are not supposed to install anything. Is there anyway to use ssh command with password like ssh -p 'password' -u 'username'

tripleee Over a year ago

The traditional solution to that is public keys.

kala Over a year ago

how can i get value in line to my local server

|

Martin · Accepted Answer · 2017-02-07 11:12:10Z

0

Depending on your requirements, you could also make the docker socket remotely available: https://docs.docker.com/engine/reference/commandline/dockerd/#/daemon-socket-option

Than, you could rewrite your script in such a way, that it connects to the local/remote docker engine:

DOCKER_HOST=unix:///var/run/docker.sock/ docker images ...
DOCKER_HOST=tcp://remote.ip:2375 docker images ...

I know that is not what you asked for, but maybe it inspires others.

answered Feb 7, 2017 at 11:12

Martin

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