Translate javascript string replace function to php

Question

I found in this site a very basic javascript function to encode text. Looking at the source code this is the string replacement code:

txtEscape = txtEscape.replace(/%/g,'@');

So the string stackoverflow becomes @73@74@61@63@6B@6F@76@65@72@66@6C@6F@77

I need a function that does the same elementary encryption in php, but I really don't understand what the /%/g does. I think in php the same function would be something like:

str_replace(/%/g,"@","stackoverflow");

But of course the /%/g doesn't work

.replace(/%/g,'@'); only replaces % characters with @, so it does nothing for the stackoverflow string. You should post the rest of your js in order to trace down what's doing the trick. :) — Mladen Ilić
– Mladen Ilić, Commented Feb 3, 2017 at 16:52

Community · Accepted Answer · 2017-05-23 12:24:23Z

1

Replace a character

Indeed, the PHP function is str_replace (there are many functions for replacements). But, the regex expression is not the same :)

See official documentation: http://php.net/manual/en/function.str-replace.php

In your case, you want to replace a letter % by @.

g is a regex flag. And // are delimiter to activate the regex mode :)

The "g" flag indicates that the regular expression should be tested against all possible matches in a string. Without the g flag, it'll only test for the first.

<?php
echo str_replace('%', '@', '%73%74%61%63%6B%6F%76%65%72%66%6C%6F%77');
?>

In PHP, you can use flags with regex: preg_replace & cie.

Escape

See this post: PHP equivalent for javascript escape/unescape There are two functions stringToHex and hexToString to do what you want :)

Indeed, the site you provided use espace function to code the message:

document.write(unescape(str.replace(/@/g,'%')));

edited May 23, 2017 at 12:24

CommunityBot

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answered Feb 3, 2017 at 16:53

Georges O.

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2 Comments

Hyperion Over a year ago

Thank you for the help, I've tried your script but what it only replaces % with @ in a string. The script in the site replaces the letter 'a' with '@61', the symbol '%' with '@25' and so on, that's what the php script should do

Georges O. Over a year ago

I edited my previous reply with a solution for the escaping issue :)

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