Python: create file if file does not exist in list

Question

I'm getting a list of files in a project, which can all range from src/app.ts to src/component/app/app.ts. What I'm looking to do is:

Currently I have:

m = re.compile(r'(ts|js)config.json$')
for file in files:
    if m.search(file):
        return True
    else:
        self.writeFile()

Which works, but it calls write multiple times when there is not match. How would I only call write after the checks are done?

Jean-François Fabre · Accepted Answer · 2017-02-01 21:00:13Z

1

You could just unindent your else block so it applies to for:

for file in files:
    if m.search(file):
        return True
else:
    self.writeFile()

note that in that case it's not as interesting as with the break case, you could simply write:

for file in files:
    if m.search(file):
        return True
self.writeFile()

since if pattern matches it returns so writeFile is not reached.

answered Feb 1, 2017 at 21:00

Jean-François Fabre♦

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Comments

Mureinik · Accepted Answer · 2017-02-01 21:00:47Z

1

You could move out writing the file to after all the checks are exhausted:

m = re.compile(r'(ts|js)config.json$')
for file in files:
    if m.search(file):
        return True

self.writeFile()

answered Feb 1, 2017 at 21:00

Mureinik

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