I am using python3.5 and I wish to write output I get in hexadecimal bytes (b'\x00', b'\x01' etc) to python strings with \x00 -> 0 and \x01 -> 1 and I have this feeling it can be done easily and in a very pythonic way, but half an hour of googling still make me think the easiest would be to make a dictionary with a mapping by hand (I only actually need it from 0 to 7).
Input Intended output
b'\x00' 0 or '0'
b'\x01' 1 or '1'
etc.
A byte string is automatically a list of numbers.
input_bytes = b"\x00\x01"
output_numbers = list(input_bytes)
Are you just looking for something like this?
for x in range(0,8):
(x).to_bytes(1, byteorder='big')
Output is:
b'\x00'
b'\x01'
b'\x02'
b'\x03'
b'\x04'
b'\x05'
b'\x06'
b'\x07'
Or the reverse:
byteslist = [b'\x00',
b'\x01',
b'\x02',
b'\x03',
b'\x04',
b'\x05',
b'\x06',
b'\x07']
for x in byteslist:
int.from_bytes(x,byteorder='big')
Output:
0
1
2
3
4
5
6
7
Not sure if you want this result, but try it
output = [str(ord(x)) for x in output]
\x0F and similar ;)
If you wiil need to convert b"\x0F" into F then use
print( hex(ord(b'\x0F'))[2:] )
or with format()
print( format(ord(b'\x0F'), 'X') ) # '02X' gives string '0F'
print( '{:X}'.format(ord(b'\x0F')) ) # '{:02X}' gives string '0F'
bmeansbytes, not binary.\x00is not string0but char with code0which can't be displayed so Python shows its code.b"\x0F"-"F"or"15"?