Filter and delete key values in json array

Question

Had generated one json array using the filter.

orders = filterFilter(vm.gridOptions.data, {
                                sampleId: 295
                        });

Here I filtered my orders array and I got this.

{
  "orders": [
    {
      "orderId": 51491,
      "orderDate": "2016-12-19T13:35:39",
      "regId": 1354,
      "sampleId": 295,
      "name": "Test",
      "nameAr": "Test"
    },
    {
      "orderId": 51493,
      "orderDate": "2016-12-19T13:35:39",
      "regId": 1354,
      "sampleId": 295,
      "name": "Test",
      "nameAr": "Test",

    }
  ]
}

Can I filter in way, It should keep only one field in the orders array. Using angular filter I need to do this.

I need an array like this.

{
  "orders": [
    {
      "orderId": 51491
    },
    {
      "orderId": 51493
    }
  ]
}

No, not using angular's filter filter. It filters. It doesn't map. But Array.map() is your friend (and Array.filter(), too, BTW). — JB Nizet
– JB Nizet, Commented Dec 20, 2016 at 7:39

Jarek · Accepted Answer · 2016-12-20 07:48:42Z

6

When you need to transform object to another, use Array.map() method. You can use it together with Array.filter() method to filter results.

orders = vm.gridOptions.data
    .filter(function (x) {
        return x.sampleId === 295;
    })
    .map(function (x) {  
        return {
            orderId: x.orderId
        };
    });

The above function returns an array of objects that contain only orderId property and sampleId is equal to 295.

answered Dec 20, 2016 at 7:48

Jarek

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Comments

tanmay · Accepted Answer · 2016-12-20 07:54:46Z

1

Alternatively, You can iterate through the orders to generate the array of objects having orderIds. Like this,

$scope.orderIDs = [];
angular.forEach($scope.orders, function(order){
    $scope.orderIDs.push({
        "orderId": order.orderId
    })
});

answered Dec 20, 2016 at 7:54

tanmay

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Comments

shary.sharath · Accepted Answer · 2022-10-14 07:14:04Z

0

I followed @Jarek answer above and implemented in my code: In my case, I had an array of file names with other details but I wanted to reduce it only names. So I first filtered array that has names begins with "sharath/subDir/12345678-"

filesList.filter(t => t.name.startsWith("sharath/subDir/123456789-")).map(x => {return x.name})

Hope it might help someone.

answered Oct 14, 2022 at 7:14

shary.sharath

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