How can I get absolute path to a script executed via ${PATH} in bash? [duplicate]

Question

I would like to get the absolute path to an executed script. Its path is /use/local/lib/debugger.sh. And it is called through $PATH=/use/local/lib from another folder. I searched an example script and found following one.

echo "path = $(cd $(dirname $0) && pwd)"

I expected I can get the absolute path, /use/local/lib. But the result was not what I expected. I got the absolute path to the directory where the script is called.

How can I get the absolute path where the script exist?

Thank you very much.

codeforester · Accepted Answer · 2017-03-11 06:22:03Z

2

Adding the -P option to pwd would make sure symlinks (if any) in the dirname of the script are properly resolved:

path=$(cd $(dirname $0) && pwd -P)

edited Mar 11, 2017 at 6:22

answered Dec 19, 2016 at 17:48

codeforester

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1 Comment

OscarAkaElvis Over a year ago

This is a help, but it doesn't solve what OP wants

OscarAkaElvis · Accepted Answer · 2016-12-19 16:19:24Z

1

Use this:

#!/bin/bash

path="path = $(cd $(dirname $0) && pwd)"
script_name="${0##*/}"

echo "${path}/${script_name}"

Or in "oneliner" style echo "path = $(cd $(dirname $0) && pwd)/${0##*/}"

answered Dec 19, 2016 at 16:19

OscarAkaElvis

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Comments

ivanivan · Accepted Answer · 2016-12-19 16:21:25Z

1

If it is really in your $PATH then the "which" command should find it.

answered Dec 19, 2016 at 16:21

ivanivan

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