Error with the array in the shell script

Question

In the following shell script, I use two arrays to store the numbers in p1.txt and p2.txt and then display them.

cat p1.txt | awk '{for(i=1;i<NF;i++) {party1[$i-1]=$i}}'
cat p2.txt | awk '{for(j=1;j<NF;j++) {party2[$j-1]=$j}}'
for ((k=1;k<10;k++))
do
    echo "${party1[$k]}"
    echo "${party2[$k]}"
done

However, when I run it with the default sh, it says Syntax error: Bad for loop variable; when I run it with bash, no numbers can be displayed. What's wrong with the script?

For the array part there is already a brilliant answer covering that. — Andreas Louv
– Andreas Louv, Commented Dec 5, 2016 at 14:51

Mustafa DOGRU · Accepted Answer · 2016-12-05 18:05:06Z

1

you can use this

#!/bin/bash
IFS=' ' read -r -a party1 <<< $(cat p1.txt)
IFS=' ' read -r -a party2 <<< $(cat p2.txt)

for ((k=1;k<10;k++))
do
    echo "${party1[$k]}"
    echo "${party2[$k]}"
done

edited Dec 5, 2016 at 18:05

answered Dec 5, 2016 at 14:22

Mustafa DOGRU

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5 Comments

haik Over a year ago

Thx. I tried this but still no numbers can be displayed.

Mustafa DOGRU Over a year ago

@haik, I updaded ans. maybe this can help you

Aserre Over a year ago

for what it's worth, both the read and mapfile versions work on my computer running wsl.

haik Over a year ago

@MustafaDOGRU It really works. I'm so grateful for your help.

haik Over a year ago

@andlrc When I replace the start index k=1 with k=0, the whole array is displayed no matter what the terminating condition is.

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