Convert array of Strings to String

Question

Hello i have a little problem with array conversion

i want to convert this array format ["x","z","y"] To this String Format ('x','y','z') with commas and parentheses.

btw this array is dynamic in size may be increased or decreased

this is my try

public static void main(String[] args) throws FileNotFoundException, IOException {
        // TODO code application logic here
        String [] arr = {"x","y","z"};
        String s = "(";

        for(int i = 0; i <arr.length;i++){
            s +="'".concat(arr[i]).concat("'") + ',' ;
            if(i == arr.length-1)
                s.replace(',', ')');
        }

        System.out.print(s);

    }

this is my output ('x','y','z', i want to replace the last comma with ')'

dont expect that the members here will write your code. tell us what is the issue you are facing with the code.. — J-J
– J-J, Commented Nov 14, 2016 at 9:48
Possible duplicate of: stackoverflow.com/questions/5925420/… and an array has a fixed capacity, use an implementation of List if you wish to have dynamic capacity. — d.j.brown
– d.j.brown, Commented Nov 14, 2016 at 9:51
my string must starts and ends with parentheses my problem with the parentheses in the end of the string. — Mohamed Nagy
– Mohamed Nagy, Commented Nov 14, 2016 at 9:53

J-J · Accepted Answer · 2016-11-14 09:58:29Z

0

This also will do the magic..

Please use StringBuilder for these kind of string operations..

for (int i = 0; i < arr.length; i++) {
            s += "'".concat(arr[i]).concat("'") + ',';
        }

        s = s.concat(")");

        System.out.print(s.replace(",)", ")"));

answered Nov 14, 2016 at 9:58

J-J

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2 Comments

Mohamed Nagy Over a year ago

('x','y','z',) i don't need the last comma

J-J Over a year ago

the last comma will get replaced

Shadov · Accepted Answer · 2016-11-14 09:53:09Z

0

s.replace(',', ')');

Here you are trying to replace the comma, but Strings in java are immutable, it means you are in fact replacing this, but not assigning the value to any variable, so it's pointless. Also, that replace will not do what you think. Instead, you need to:

s = s.substring(0, s.length()-1);

This is gonna remove the last character from the String (that is extra comma at the end). Then just append ) to it and you are done.

answered Nov 14, 2016 at 9:53

Shadov

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Comments

Eritrean · Accepted Answer · 2016-11-14 10:02:57Z

0

You can also use the String.join method :

public static void main(String[] args) {
    String [] arr = {"x","y","z"};        
    String s  = String.join("','", arr);
    s = "('"+s+"')";
    System.out.print(s);
}

answered Nov 14, 2016 at 10:02

Eritrean

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Comments

Younes HAJJI · Accepted Answer · 2016-11-14 10:46:48Z

0

You can try this, using String.format and String.join

    String[] arr = { "x", "y", "z" };
    String s = String.format("('%s')", String.join("','", arr));
    System.out.println(s);

It print

('x','y','z')

Edit

If you are using jdk7, you can use StringBuilder to avoid performance issues, as shown in the code:

    String[] a = { "x", "y", "z" };
    StringBuilder b = new StringBuilder("(");
    for (int i = 0; i < a.length; i++) {
        b.append("'").append(String.valueOf(a[i])).append("'");
        b.append((i == a.length - 1) ? ")" : ", ");
    }
    System.out.println(b);

It print

('x','y','z')

edited Nov 14, 2016 at 10:46

answered Nov 14, 2016 at 10:07

Younes HAJJI

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2 Comments

Mohamed Nagy Over a year ago

i'm using jdk 7

Younes HAJJI Over a year ago

so you can try the code with the StringBuilder to avoid performance issues if you concatenate using String

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