Angular2 : Input binding

Question

I am trying to bind the input with the component as defined here :

https://angular.io/docs/ts/latest/cookbook/component-communication.html#!#parent-to-child but component name is never shown

I am even trying to do the console.log but it shows:

componentName isundefined

<div ng-switch="accessLevel">
<div class="customer" ng-switch-when="ENABLED">This is customer data</div>
<div class="customer-blurr"  ng-switch-when="DISABLED"> This is disabled Customer Data</div>
<div class="customer-blurr" ng-switch-default> <demo-error [componentName]="componentname"></demo-error></div>
</div>

and in error.html

<div> you are not allowed to access {{component}} </div>

Demo Error :

import { Component, OnInit,Input } from '@angular/core';

@Component({
  selector: 'demo-error',
  templateUrl: './error.component.html',
  styleUrls: ['./error.component.css']
})
export class ErrorComponentDemo implements OnInit {
@Input() public componentName:string;
  constructor() { 
    console.log("componentName is" +this.componentName)
  }

  ngOnInit() {
  }

}

And in **CustomerComponent:**

@Component({
  selector: 'customer',
  templateUrl: './customer.component.html',
  styleUrls: ['./customer.component.css']
})
export class CustomerComponent extends SuperChildComponent{
  public allowed: boolean = false;
  public  accessLevel:AccessLevel =null;
  public componentname:string;

  constructor(private authenticationService : AuthorizationService) {
    super();
    this.componentname=this.constructor.name;
     this.accessLevel=this.authenticationService.isUserLoggedIn()?this.authenticationService.componentAccessLevel(this.constructor.name):null;
  }

what am i missing here ?

Thanks

Ivafo · Accepted Answer · 2016-11-09 10:44:29Z

2

Your input won't be available in the constructor yet. Try this f.e.

@Input set componentName(value: string) { 
  if(value != null && value != undefined) {
    this._componentName = value; console.log(this._componentName); 
  }
}

_componentName: string

This way you can do your calls of methods in the if statement within the set

answered Nov 9, 2016 at 10:44

Ivafo

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Comments

John Baird · Accepted Answer · 2016-11-09 11:03:09Z

2

You need to lose the '[]' if your input is a string.

componentName="componentname"

answered Nov 9, 2016 at 11:03

John Baird

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