JavaScript Regex Match Value + Comma and Replace with Empty or space

Question

I am using javascript .replace function to replace match content/pattern but problem it replace match content but didn't get the comma associate with, Like:

i have var a = 'gJDjOw0ern8,-4oCq2Vw4GQ,fjsrhmUhK60';
and b = 'gJDjOw0ern8,-4oCq2Vw4GQ';

and i want to remove only match values, like the above example have i need this output after replace:" a = 'fjsrhmUhK60';

But what i am getting is: a =' ,fjsrhmUhK60';

everytime values replace but the associate comma didn't replace with empty or space.

my code: a = a.replace(b,'');

i don't want to remove all commas, reason after every unique value have its comma separator,

5 unique values have 4 commas:

654987987dsfdsf,5487987fsdfdsfsd,dsf8ds7987987,dsfdsfd779,sdfdsfdf

so only want to remove the matched value and the associated comma with space or empty.

CrayonViolent · Accepted Answer · 2016-10-26 18:05:16Z

2

An alternative to the regex approach:

// arg1 : the source string
// arg2 : the values to remove from source string
function stringDiff(a,b){
  var b=b.split(',');
  return a.split(',').filter(function(v){
    return b.indexOf(v)==-1;
  }).join(',');
}

var a = 'gJDjOw0ern8,-4oCq2Vw4GQ,fjsrhmUhK60';
var b = 'gJDjOw0ern8,-4oCq2Vw4GQ';

stringDiff(a,b); // return:fjsrhmUhK60

answered Oct 26, 2016 at 18:05

CrayonViolent

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1 Comment

Abdullah Over a year ago

You understand what i want, without any bug its working perfectly, amazing job Crayon.

anubhava · Accepted Answer · 2016-10-26 18:02:59Z

1

You can use:

var r = a.replace(new RegExp(b + ",*"), '');
//=> "fjsrhmUhK60"

new RegExp(b + ",*") will build a regex using variable b followed by 0 or more comma.

PS: If a and b may contain regex meta characters then you will need to escape those chars in b. Something like this should work:

var r = a.replace(new RegExp(b.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + ",*"), '');

edited Oct 26, 2016 at 18:02

answered Oct 26, 2016 at 17:55

anubhava

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9 Comments

Abdullah Over a year ago

Your first example work well it create new bug, which is i have 4 unique id's now: 'saHJ_S-MEiY,SEUXMVt6Fik,6KtOcX8xOY8,jmMn4zzdyqc,ARTDCAGGS5k And i matched: var b = 'saHJ_S-MEiY,ARTDCAGGS5k'; you code not work when i match the first id and the last id, but between ids i can match and replace with associate comma now, can you check this what's now new issue its.

anubhava Over a year ago

Didn't get your comment. Can you clarify what is a and what is b and what is expected output?

CrayonViolent Over a year ago

bad regex. try with a='foo,bar';b='bar'; or a='foo,bar';b='foobar,bar'

anubhava Over a year ago

@CrayonViolent: Use: a.replace(new RegExp(",*" + "\\b" + b + ",*"), '')

CrayonViolent Over a year ago

still bad regex. again, try a='foo,bar';b='foobar,bar'

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