How to convert a selenium webelement to string variable in python

Question

from selenium import webdriver
from time import sleep
from selenium.common.exceptions import NoSuchAttributeException
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get('https://www.linkedin.com/jobs/search?locationId=sg%3A0&f_TP=1%2C2&orig=FCTD&trk=jobs_jserp_posted_one_week')
jobtitlebutton = driver.find_elements_by_class_name('job-title-link')
print(jobtitlebutton)

The output is a selenium webelement in the form of a list. I want to convert it into a string variable so that the list can contain all the jobtitles in text format. If I can get assistance in this it will be great. Thanks in advance.

Do you need list of links or list of jobs (e.g. "Datacenter Technician", "Test Manager")? — Andersson
– Andersson, Commented Oct 13, 2016 at 4:43

Andersson · Accepted Answer · 2018-11-25 09:27:52Z

8

In case, if you need a list of links to each job:

job_list = []
jobtitlebuttons = driver.find_elements_by_class_name('job-title-link')
for job in jobtitlebuttons:
    job_list.append(job.get_attribute('href'))

In case, if you want just a job titles list:

job_list = []
jobtitlebuttons = driver.find_elements_by_class_name('job-title-text')
for job in jobtitlebuttons:
    job_list.append(job.text)

edited Nov 25, 2018 at 9:27

answered Oct 13, 2016 at 4:50

Andersson

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4 Comments

Kaila Shanmukh Over a year ago

Thanks alot it did helped me alot.

Kaila Shanmukh Over a year ago

I also would want to know how I can click each of the job title and extract the job description for which the class name is 'content'.

Andersson Over a year ago

I guess you should loop through job_list of links and do something like description = "/n".join([i.text for i in driver.find_elements_by_xpath('//div[@class="content"]//ul/li')])

Kaila Shanmukh Over a year ago

Thanks alot. It surely helps

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