How to execute function when parameter is array or callable?

Question

Look this example code:

I'm getting the error:

Fatal error: Uncaught Error: Cannot use object of type Closure as array in C:\xampp\htdocs\dermaquality\test.php:11 Stack trace: #0 C:\xampp\htdocs\dermaquality\test.php(20): test(Object(Closure)) #1 {main} thrown in

$array = array(
    'hello' => function() {
        echo "HEllo world";
    }
);

function test( $func )
{
    if (is_callable( $func['hello'] )) {
        $func['hello']();
    }
    else {
        $func();
    }
}

echo "Executing 1 <br/>";
test( $hello = function() {"Hello world";} );
echo "Executing 2 <br/>";
test( $array['hello'] );
exit;

How can I call $func if $func is function or if $func['hello'] is function?

Thanks.

Try to change the if to do the reverse: if (is_callable($func)) $func; else $func['hello'](); — David Rojo
– David Rojo, Commented Oct 3, 2016 at 16:03

Marek Janoud · Accepted Answer · 2016-10-03 16:07:15Z

1

Problem is in if (is_callable( $func['hello'] )) { because you dont know if $func is an array.. btw you dont put array as parameter in test( $array['hello'] ); you put just function...

function test( $func )
{
    if (is_callable($func)) {
        $func();
    }
    else if (is_array($func)){
        if(isset($func['hello']) && is_callable($func['hello'])){
            $func['hello']();
        }else{
            // unknown what to call
        }
    }else{
        // unknown what to call
    }
}

answered Oct 3, 2016 at 16:07

Marek Janoud

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7 Comments

Marek Janoud Over a year ago

is_callable is just function, never know if another was called or not, in first is_callable($func) is not important what value is in variable $func because function is_callable will check if its callable, before you use $func['hello'] you must know that $func is an array thats why

Marek Janoud Over a year ago

just the value of variable will pass to function throught parameter, so some_function([]); is the same as $array = []; some_function($array); in context of the function

Marek Janoud Over a year ago

when you write $func['hello'] you read value of array $func with key hello, if $func is not array then error will occur

Marek Janoud Over a year ago

just try something like $string = 'test'; $string[0]; or $array = ['test']; echo $array; or $array = ['test']; $array['whatever']; all of them will fail...

Marek Janoud Over a year ago

that means the type of value is important for functions because they know how to handle only that types for which they are prepared to work

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