Variable defined in a function, needed within a function within this function - Python [duplicate]

Question

I need to define a variable within a function and use it in a function that is within the original function. For example,

def go_to_next_function():
    globvar = 0
    def add_one_to_globvar():
        global globvar  
        for i in range(10):
            globvar += 1
            print(globvar)
    add_one_to_globvar()
go_to_next_function()

Now I know if globvar is defined outside all of the functions then it would work, but I want it to be defined inside the go_to_next_function() function. Any ideas? Thanks.

python2 or python3? In python3 you can use nonlocal.

Aran-Fey
– Aran-Fey

2016-08-25 13:36:20 +00:00
Commented Aug 25, 2016 at 13:36 — Aran-Fey
– Aran-Fey, Commented Aug 25, 2016 at 13:36
It is in Python 3

123Bear Honey
– 123Bear Honey

2016-08-25 13:37:09 +00:00
Commented Aug 25, 2016 at 13:37 — 123Bear Honey
– 123Bear Honey, Commented Aug 25, 2016 at 13:37

mgilson · Accepted Answer · 2016-08-25 13:42:02Z

1

If you are using python3.x, you can use the nonlocal keyword rather than global and your function should work.

If you're on python2.x, you're stuck with old hacks like putting the value in a container and mutating that. It's an ugly hack (which is why nonlocal was added in the first place):

def go_to_next_function():
    closure_var = [0]
    def add_one():
        closure_var[0] += 1
        print closure_var[0]
    add_one()
go_to_next_function()

edited Aug 25, 2016 at 13:42

answered Aug 25, 2016 at 13:36

mgilson

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1 Comment

123Bear Honey Over a year ago

Thank you. I'm using Python 3

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