I am trying to get jsonb result based on matching key. I have DB table "listings" with number and data column.
number | data
1 | {"name": "XYZ company", "city": "toronto", "province": "ON", "people" : [
{ "firstName": "tom", "lastName": "hanks",
"phonenumber": [{"type": "mobile", "Number": "111111"}],
"Email": [{"type": "business", "address": "[email protected]"},{"type": "personal", "address": "[email protected]"}] },
{ "firstName": "sandra", "lastName": "petes",
"phonenumber": [{"type": "mobile", "Number": "333"}, {"type": "home", "Number": "444"}],
"Email": [{"type": "business", "address": "[email protected]"}]
}
]}
I need to pull all values for data column with keys -
- people->firstname
- people->lastName
- people->phonenumber->Number
- people->Email->address
What I achieved so far is:
SELECT number
,jonb_array_length(jsonb_extract_path(data,'people')) as people_count
,jsonb_extract_path(data,'people','0','firstname') as FirstName
,jsonb_extract_path(data,'people','0','lastname') as LastName
,jsonb_extract_path(data,'people','0','email','Address'") as personEmail
,jsonb_extract_path(data,'people','0','phonenumber','Number') as personPhone
FROM listings
WHERE number='1';
However, this only gives me 0th element of people, I need to find all elements. Is there any way to achieve this in single query.
Thanks for your time!