Python script executing two other python scripts asynchronously

Question

I have a python script myscript that when run it "stays open" with a GUI. I would like to write a python script launching myscript two times like this:

bash>python runNTimes.py 2

I have the following code for runNTimes.py

import subprocess
for i in range(int(sys.argv[1])):
    subprocess.call(['python', 'myscript.py'])

The problem is that this happens synchronously, i.e. once I launch the first in a subprocess the second subprocess is not launched until the first terminates.

A minimal example for myscript.py:

try: 
        import Tkinter as tk # for Python2
except: 
        import tkinter as tk # for Python3

win=tk.Tk()
win.mainloop()

Call blocks, use Popen

Padraic Cunningham
– Padraic Cunningham

2016-07-16 14:56:23 +00:00
Commented Jul 16, 2016 at 14:56 — Padraic Cunningham
– Padraic Cunningham, Commented Jul 16, 2016 at 14:56
@PadraicCunningham You beat my ninja edit

Rolf of Saxony
– Rolf of Saxony

2016-07-16 15:06:37 +00:00
Commented Jul 16, 2016 at 15:06 — Rolf of Saxony
– Rolf of Saxony, Commented Jul 16, 2016 at 15:06

Rolf of Saxony · Accepted Answer · 2016-07-16 15:04:29Z

1

Use Popen instead: call() blocks Popen() doesn't

from subprocess import Popen
import sys
for i in range(int(sys.argv[1])):
    Popen(['python', 'synccall1.py'])

synccall1.py

try: 
        import Tkinter as tk # for Python2
except: 
        import tkinter as tk # for Python3

win=tk.Tk()
win.mainloop()

edited Jul 16, 2016 at 15:04

answered Jul 16, 2016 at 14:55

Rolf of Saxony

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