Add element into Array

Question

I´m trying to dynamically add an element into an array:

   array=("element1" "element2" "element3")
   fa=()
   # now loop through the above array
   for i in "${array[@]}"
   do
      fa+=("$i")
      # or do whatever with individual element of the array
   done

   echo $fa

But it's returning element1.

I've tried with an index, but I'm getting the same result:

fa[index]="$i"
((index++))

Am I doing something wrong here?

A side-note, you may double check whether all the shells support fa+=("$i") style. — sjsam
– sjsam, Commented Jul 11, 2016 at 11:48

sjsam · Accepted Answer · 2016-07-11 11:42:13Z

17

The problem is with printing ie echo $fa. This is equivalent to echo ${fa[0]} which means the first element of the array, so you gotelement1

echo "${fa[@]}"

should give you the entire array.

Reference

[ This ] should give you a nice description about bash arrays.

answered Jul 11, 2016 at 11:42

sjsam

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