I have 2 buttons with the same value and class, they are identical.
<input class="button" value="Ir" type="submit">
I want to click the second one, that it is in <div class="smallfont">
How can i do that with python Selenium? Thanks ;D
INPUT CODE <------- IMAGE
You can grab references to both elements and just click the second one.
buttons = driver.find_elements_by_css_selector("input.button");
buttons[2].click()
Here is the example from the documentation:
<html>
<body>
<form id="loginForm">
<input name="username" type="text" />
<input name="password" type="password" />
<input name="continue" type="submit" value="Login" />
<input name="continue" type="button" value="Clear" />
</form>
</body>
<html>
login_form = driver.find_element_by_xpath("/html/body/form[1]")
login_form = driver.find_element_by_xpath("//form[1]")
login_form = driver.find_element_by_xpath("//form[@id='loginForm']")
input[1] is an array, starting at 1, so in your case, it should looks like this(Corrected, following comment):
button = driver.find_element_by_xpath("//form[@class='smallfont']/input[@value='Ir'][@type='submit'][2]")
button.click()
From:
http://selenium-python.readthedocs.io/locating-elements.html
If I am correct that there is only one submit button in the div of class "smallfont" (the duplicate button is in a different div that does not have that class), then you can simply use a path similar to:
//div[@class='smallfont']/input
Try to resolve in below way.
String cssSelectorOfSameElements="input[type='submit'][id='button']";
List<WebElement>a=driver.findElements(By.cssSelector(cssSelectorOfSameElements);
a.get(0).click();
a.get(1).click();
a.get(2).click();
Now depends on your requirement you can click on particular tab. Hope this works.
