ASP.NET MVC. Create model to convert into JSON-object (with dynamic name property)

Question

I need to generate Json-output like this:

{
    "01:30":{
        "FREE":true,
        "PRICE":3500
     },
    "03:00":{
        "FREE":true,
        "PRICE":2500
    },
    "13:30":{
        "FREE":true,
        "PRICE":2500
    }
}

My problem here is time string - its dynamic from one entry to another. I can not figure out how to construct my c# class (model) that will be serialized into proper json result. My model looks like this now:

public class ScheduleViewModel
{
    public ScheduleInnerViewModel TIME { get; set; }
}

public class ScheduleInnerViewModel
{
    public bool FREE { get; set; }
    public int PRICE { get; set; }
}

Output result is (wrong):

[
    {"TIME":{
        "FREE":true,
        "PRICE":3500
     }},
    {"TIME":{
        "FREE":true,
        "PRICE":2500
    }},
    {"TIME":{
        "FREE":true,
        "PRICE":2500
    }}
]

I use standard way to generate json result from controller:

List<ScheduleViewModel> model = new List<ScheduleViewModel>();
//fill the model...
return this.Json(model, JsonRequestBehavior.AllowGet);

"01:30" you need a variable to represent this

COLD TOLD
– COLD TOLD

2016-06-28 16:48:56 +00:00
Commented Jun 28, 2016 at 16:48 — COLD TOLD
– COLD TOLD, Commented Jun 28, 2016 at 16:48

Veverke · Accepted Answer · 2016-06-28 16:55:06Z

2

What about having a dictionary where the key is a string (your timestamp) and the data is your model class ?

Like:

Dictionary<string, ScheduleInnerViewModel> dic = new Dictionary<string, ScheduleInnerViewModel>();

dic.Add("01:30", new ScheduleInnerViewModel{ Free = false, Price = 100 });
dic.Add("04:25", new ScheduleInnerViewModel{ Free = false, Price = 200 });
dic.Add("13:00", new ScheduleInnerViewModel{ Free = true, Price = 0 });

var json = JsonConvert.SerializeObject(dic, new JsonSerializerSettings { Formatting = Newtonsoft.Json.Formatting.Indented });

Console.WriteLine(json);

Output:

answered Jun 28, 2016 at 16:55

Veverke

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1 Comment

Sam Alekseev Over a year ago

Thank you! Simple and elegant solution.

Community · Accepted Answer · 2017-05-23 12:32:58Z

2

Try the unaccepted answer from this post. It uses a Dictionary to create the property name (key) and then you can use your ScheduleInnerViewModel as the value so something like:

 var obj = new Dictionary<string, ScheduleInnerViewModel>();

edited May 23, 2017 at 12:32

CommunityBot

11 silver badge

answered Jun 28, 2016 at 16:53

Ju66ernaut

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1 Comment

Veverke Over a year ago

seems I came a minute late :)

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