How to delete multiple objects whose id='null' -JS

Question

I have list of objects whom I want to loop through to see for the value of a key, in this I want to remove objects whode id= "null". Below is snippet:

obj: {
     after:{
        id: null,
        name:'test',
        address: '63784hgj'
     },
      before:{
        id: 678346,
        name:'test',
        address: '63784hgj'
     },
      single:{
        id: null,
        name:'test',
        address: '63784hgj'
     },
      range:{
        id: 65847,
        name:'test',
        address: '63784hgj'
     }
 }

I tried some sloppy way of doing this, considering I know the object that has id with null value:

obj.abc.id.destroy;
obj.abc3.id.destroy;

below is the way the object is seen:

is there any way I could remove objects that dont have null values for their id's?

Thx~

Pretty sure you can do delete obj.single in this case. if you wanted to loop, maybe loop var prop in obj and if (obj[prop].id === null), you delete obj[prop] — vtange
– vtange, Commented Jun 23, 2016 at 0:00
But the object you want to delete is on a property of another object, right? — user1106925
– user1106925, Commented Jun 23, 2016 at 0:00

vtange · Accepted Answer · 2016-06-23 00:07:09Z

2

If you want to just delete single: delete obj.single;

If you want to delete multiple objects within obj:

for (var prop in obj){
    if (obj[prop].id === null){
        delete obj[prop];
    }
}

answered Jun 23, 2016 at 0:07

vtange

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Comments

Dan · Accepted Answer · 2016-06-23 00:07:31Z

1

you can use the delete operator.

e.g.

for (var prop in obj) { 
    var item = obj[prop];  
    if (!item.id) {
        delete item; 
    }
}

edited Jun 23, 2016 at 0:07

answered Jun 22, 2016 at 23:58

Dan

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2 Comments

user1234 Over a year ago

how about for deleting multiple object in one func? I'd need to remove the single and after object coz both of them have prop with null values

Dan Over a year ago

just loop through each item in the object

Morteza Tourani · Accepted Answer · 2016-06-23 18:10:44Z

1

I think these are simpler answers than above (with respect to line of code):

var obj= {
     after:{ id: null, name:'test', address: '63784hgj' },
      before:{ id: 678346, name:'test', address: '63784hgj' },
      single:{ id: null, name:'test', address: '63784hgj' },
      range:{ id: 65847, name:'test', address: '63784hgj' },
 };
// Solution #1: set items to new object.
var newObj = {};
Object.keys(obj)
  .forEach(k => obj[k].id && (newObj[k] = obj[k]));

// Solution #2: delete unwanted from object itself.
Object.keys(obj)
  .forEach(k => !obj[k].id && delete obj[k]);

console.log(newObj);
console.log(obj);

answered Jun 23, 2016 at 18:10

Morteza Tourani

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