How to loop without getting IndexError on python?

Question

I tried to loop for url_data. url_data is an array of strings. I get an IndexError that reads:

keywords[i]=urlparse.urlparse(url_data[i])
IndexError: only integers, slices (`:`), ellipsis (`...`), numpy.newaxis (`None`) and integer or boolean arrays are valid indices

My code:

import os
import csv
import numpy as np
import pandas
import urlparse
from numpy import genfromtxt

os.chdir("C:\Users\EDAWES01\Desktop\Cookie profiling")
data = pandas.read_csv('activity_url.csv', delimiter=';')
data_read=np.array(data)
quantity = data_read[:, 2]
url_data = data_read[quantity==1][:,1] 
url_data #extract URL data

keywords=[]

for i in url_data:
  keywords[i]=urlparse.urlparse(url_data[i])
  keywords[i]=keywords[2] #this is the path element
  keywords[i]=keywords[i].split("/")

keywords

keywords is initialized to an empty list. So there are no valid indices. The loop tries to use i as an index, multiple times, but (1) i apparently isn't an integer and (2) even if it were, it would be out of range since they're all out of range for an empty list. — Tom Karzes
– Tom Karzes, Commented Jun 22, 2016 at 7:44
keywords is a error. But the error message is about url_data[i]. url_data and i are str. str[str] won't work — qvpham
– qvpham, Commented Jun 22, 2016 at 7:51

sameera sy · Accepted Answer · 2016-06-22 07:55:38Z

1

try this loop instead

for i in xrange(0,len(url_data)):
     keywords[i]=urlparse.urlparse(url_data[i])

answered Jun 22, 2016 at 7:55

sameera sy

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1 Comment

Abdul Fatir Over a year ago

xrange(len(list)) is not the pythonic way.

Abdul Fatir · Accepted Answer · 2016-06-22 07:57:07Z

1

You're doing it wrong. If you want both the element and index, use enumerate().

for idx,url in enumerate(url_data):
    keywords[idx]=urlparse.urlparse(url_data[idx])
    # or it could be
    keywords[idx]=urlparse.urlparse(url)  
    # both of these will still raise IndexError for keywords

Now, coming to the issue of keywords which is an empty list so you'll get IndexError for that too. I think you want to do the following instead.

keywords.append(urlparse.urlparse(url))

answered Jun 22, 2016 at 7:57

Abdul Fatir

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Comments

thomas · Accepted Answer · 2016-06-22 08:41:54Z

0

From the looks of your code keywords should be either:

keywords = {}
keywords = dict()

print(i) to figure out what you're doing.

answered Jun 22, 2016 at 8:41

thomas

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