Why is the PHP function "implode" returning the string "array"?

Question

I am calling the following function:

function buildInStmt($array)
{
    if (is_array($array)) {
        $in = implode(',', $array);
    } else $in = "'" . $array . "'";
    var_dump("in=" . $in); 
    var_dump("$array=" . $array); 
    return $in;
}

...

    if (!isset($_REQUEST["form-type"]) || empty($_REQUEST["form-type"])) {
        throw new Exception('You must select a form type.');       
    }
    $forms = buildInStmt(array($_REQUEST["form-type"]));

The var_dumps from the function are returning:

string 'in=Array' (length=8)

string 'Array=Array' (length=11)

string 'in=Array' (length=8)

string 'Array=Array' (length=11)

string 'in=1' (length=4)

string 'Array=Array' (length=11)

The var_dump(array($_REQUEST["form-type"])); from the call returns:

array (size=1) 0 => array (size=2) 0 => string '4' (length=1) 1 => string '7' (length=1)

Why isn't implode returning a comma delimited string?

Iff you elect to downvote this question, please explain the reason so I can learn from my mistakes.

Thanks, Francisco. I am passing an array from ajax. Works now. — ron tornambe
– ron tornambe, Commented Jun 5, 2016 at 15:35

Francisco Presencia · Accepted Answer · 2016-06-05 15:35:01Z

1

array (size=1) 0 => array (size=2) 0 => string '4' (length=1) 1 => string '7' (length=1)

Is roughly equivalent to

$var = [
  0 => [
    0 => '4',
    1 => '8'
  ]
]

So it seems that you have an array of arrays. Try not adding an unneeded array from your code:

buildInStmt($_REQUEST["form-type"])

answered Jun 5, 2016 at 15:35

Francisco Presencia

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