Create a JSON object from a single PHP variable with key

Question

I am trying to send a single PHP variable to a client via json. However, if I generate the string myself and pass it into json_encode, it adds / around the key. I am using:

$threadID = mysqli_insert_id($Thesisdb);
$threadtoJ='{"id":'.$threadID.'}';
echo json_encode($threadtoJ);

I am looking for an output like this: {"id","12"}

You want to encode your data to JSON, so you don't want to create the JSON yourself. You probably want to do something like this ["id" => $threadID], where you create an array, which you then encode with the function to JSON. — Rizier123
– Rizier123, Commented May 7, 2016 at 14:10

Michael Gulik · Accepted Answer · 2017-02-03 19:05:14Z

3

echo json_encode(array("id" => 12));

Is the correct answer. Thanks @u_mulder

edited Feb 3, 2017 at 19:05

answered May 7, 2016 at 14:15

Michael Gulik

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1 Comment

Stuart Over a year ago

Indeed, you need a regular array in php, then json_encode it, and you're on.

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