Python, loop program

Question

Can someone tell me what i am doing wrong? I am writing a program using loops in Python 3.x, but when i execute program i am getting a traceback error:

multiple of 13 is 195 and factors are as follows Traceback (most recent call last): File "C:/Users/Darlene/Desktop/Chapter 4/program4_2.py", line 19, in list1.append(j) AttributeError: 'dict' object has no attribute 'append'

this is the code i entered:

def main():
    for i in reversed(list(range(100,201))):
    if i%13==0:
        print("multiple of 13 is",i,"and factors are as follows")
        list1 = {}
        for j in list(range(2,i+1)):
            if i%j == 00:
            list1.append(j)
        print(list1)
main()

If I remember correctly, list1 = {} declares a dictionary, not a list, thus there is no append method associated with it. — Luke Joshua Park
– Luke Joshua Park, Commented Apr 10, 2016 at 1:01

Xiflado · Accepted Answer · 2016-04-10 01:11:31Z

1

As commented by Luke Park, list1 = {} will declare a dictionary. What you need is list1 = [].

Also, range will already return a range type that can be handled by most methods and loops so there's no need to cast it to a list.

answered Apr 10, 2016 at 1:11

Xiflado

18611 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

tanaydin · Accepted Answer · 2016-04-10 01:10:11Z

0

list1 must be an list like so...

list1 = []

you defined it as an dict, and as python said

'dict' object has no attribute 'append'

answered Apr 10, 2016 at 1:10

tanaydin

5,32632 silver badges50 bronze badges

Collectives™ on Stack Overflow

Python, loop program

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related