Swift: Convert an array of objects into a string?

Question

I want to convert an array of users into a string of their names.

For example:

class User {
    var name: String

    init(name: String) {
        self.name = name
    }
}

let users = [
    User(name: "John Smith"),
    User(name: "Jane Doe"),
    User(name: "Joe Bloggs")
]

Is this a good way to get the String: "John Smith, Jane Doe, Joe Bloggs"?
```
let usersNames = users.map({ $0.name }).joinWithSeparator(", ")
```
What if I want the last comma to be an ampersand? Is there a swift way to do that, or would I need to write my own method?

Related: stackoverflow.com/questions/8586141/…

ma11hew28
– ma11hew28

2016-04-07 22:27:10 +00:00
Commented Apr 7, 2016 at 22:27 — ma11hew28
– ma11hew28, Commented Apr 7, 2016 at 22:27

Leo Dabus · Accepted Answer · 2016-04-08 01:11:48Z

1

You can create a computed property. Try like this:

class User {
    let name: String
    required init(name: String) {
        self.name = name
    }
}

let users: [User] = [
    User(name: "John Smith"),
    User(name: "Jane Doe"),
    User(name: "Joe Bloggs")
]

extension _ArrayType where Generator.Element == User {
    var names: String {
        let people = map{ $0.name }
        if people.count > 2 { return people.dropLast().joinWithSeparator(", ") + " & " + people.last! }
        return people.count == 2 ? people.first! + " & " + people.last! : people.first ?? ""
    }
}

print(users.names) // "John Smith, Jane Doe & Joe Bloggs\n"

edited Apr 8, 2016 at 1:11

answered Apr 7, 2016 at 22:42

Leo Dabus

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Comments

ma11hew28 · Accepted Answer · 2016-04-08 00:19:22Z

-1

You can use reduce:

users.reduce("", combine: { ($0.isEmpty ? "" : $0 + ", ") + $1.name })

Try this:

func usersNames() -> String {
    var usersNames = users[0].name
    if users.count > 1 {
        for index in 1..<users.count {
            let separator = index < users.count-1 ? ", " : " & "
            usersNames += separator + users[index].name
        }
    }
    return usersNames
}

edited Apr 8, 2016 at 0:19

answered Apr 7, 2016 at 22:40

ma11hew28

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2 Comments

ma11hew28 Over a year ago

Right, because it's answering the first question.

ma11hew28 Over a year ago

OK. That's OK. Thanks! :-)

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