Simple Python shell wrapper script (using os.execv?)

Question

I want to add a wrapper around a specific shell command. This will run in Linux only and I don't care about cross platform support. This code works, but is there a better way to achieve this? Or am I opening myself up to any weird behavior?

import os
import sys

# Do my personal validation here
do_some_validation(sys.argv) 

# Now call the real program
os.execv('/usr/bin/some-command', sys.argv)

Thanks!

pyrrhic · Accepted Answer · 2017-11-28 17:09:35Z

3

You may use subprocess

import subprocess
subprocess.call(['/usr/bin/some-command', arg1, arg2])

subprocess is better than os in a way, in that it has more control over execution of a command, whereas os just throws it to bash.

edited Nov 28, 2017 at 17:09

pyrrhic

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answered Mar 29, 2016 at 9:06

Alexey Smirnov

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2 Comments

user3827132 Over a year ago

What does subprocess offer me specifically? When I was googling before posting this I saw a variation of your comment all over, but in this case I want to replace the executable with the one I am wrapping. I have no need to get the return code, out/err, do error handling, etc, etc.

Alexey Smirnov Over a year ago

In your case you can stay with os, of course. No need to switch to subprocess at all, but in future if you are going to expand your script you may need some return codes,pipes, etc, oum ya need it.

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