I've found lots of similar posts, but none yet that fully satisfy the question: How can I get the min & max values from the following 2D array in javascript?
[[1,2,3],[4,5,6],[7,8,9]]
i.e., return 1 and 9.
this question isn't quite what I'm after (as the user wants to ignore col 0), and here asks only for a 1D array.
The accepted answer here asks only for the first value of each set.
Can anyone point me to the correct (accepted) method? Many thanks!
How about flattening the array, then using Math.max.apply and Math.min.apply:
var arr = [[1,2,3],[4,5,6],[7,8,9]].reduce(function (p, c) {
return p.concat(c);
});
var max = Math.max.apply(null, arr); // 9
var min = Math.min.apply(null, arr); // 1
Try to use traditional way of finding min and max from an array,
var x = [[1, 2, 3],[4, 5, 6],[7, 8, 9]];
var min,max;
x.forEach(function(itm) {
itm.forEach(function(itmInner) {
min = (min == undefined || itmInner<min) ? itmInner : min;
max = (max == undefined || itmInner>max) ? itmInner : max;
});
});
console.log(max,min); // 9, 1
And you can see a performance test below,
Use Array.prototype.reduce in order to flatten the array and Array.prototype.sort or Math.Min\Math.Max in order to find the max\min values.
var arr = [[9,2,3],[4,5,6],[7,8,1]];
var flattenedArr = arr.reduce(function(arr1, arr2) { return arr1.concat(arr2)});
var sorted = flattenedArr.sort();
var min = sorted[0];
var max = sorted[sorted.length - 1];
try this
var array = String([[1,2,3],[4,5,6],[7,8,9]]).split(",").map( function(value){ return parseInt(value); } );
var max_of_array = Math.max.apply(Math, array);
var min_of_array = Math.min.apply(Math, array);
function minMaxIn2D(arr) {
var min,max;
for(var i in arr) {
for(var j in arr[i]){
min = min - arr[i][j] <= 0 ? min : arr[i][j] ;
max = max - arr[i][j] >= 0 ? max: arr[i][j];
}
}
console.log(min, max)
}using flat
const arr = [[1,2,3],[4,5,6],[7,8,9]]
const max = Math.max(...arr.flat())
const min = Math.min(...arr.flat())
console.log(min, max)
