Capture output of remote command in variable inside of a shell script

Question

I have a script I want to run on remote via ssh. It checks if there is a process running and should try to kill it, if it exists. Now, my code looks like this:

ssh my_prod_env << ENDSSH
...
pid=$(pgrep -f "node my_app.js")
echo $pid
# kill process with $pid
...
exit
ENDSSH

The problem lies here: I cannot capture output of pgrep command in variable. I tried with $(), backticks, pipe then read and maybe other approaches, but all without success.

I would like to do it all in one ssh session.

Now I am thinking the output of command goes to the output stream I cannot access in my script. I might be wrong, though. Either way, help will be appreciated.

I guess it works but can I avoid connecting once again only for this command? I have to stay on remote server to do something else after this command finishes and would like to do it all in one ssh session. — ezamur
– ezamur, Commented Mar 3, 2016 at 10:32

agilob · Accepted Answer · 2016-03-03 10:42:14Z

0

Ok, after you provided in comments more info what you want, I believe this is the correct answer to your question:

ssh my_prod_env -t 'pgrep -f "node my_app.js"'

This will call the command and leave you logged on the server

answered Mar 3, 2016 at 10:42

agilob

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Community · Accepted Answer · 2017-05-23 12:23:43Z

0

This is what fixes the thing - "escaping" the ENDSSH tag.

ssh my_prod_env << /ENDSSH
...
# capture output of remote commands in remote variables
...
ENDSSH

Problem was that my vars were local and I was trying to capture output of remote commands in them.

This question/answer helped me realize what is going on: How to assign local variable with a remote command result in bash script?

So, my question could be marked as duplicate or something similar, I guess.

edited May 23, 2017 at 12:23

CommunityBot

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answered Mar 3, 2016 at 11:10

ezamur

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