jQuery: If key exists in array, get value

Question

I am trying to see if a certain key exists in an array, and if so, return it's value:

if(jQuery.inArray(live_ids.grade, item.SizePrice) !== -1) {

    console.log(item.SizePrice);

}

This will return:

{"8":"15.00","7":"20.00","1":"6.00","6":"11.00","2":"7.00","3":"8.00","4":"9.00","5":"10.00","11":"20.00","9":"10.00","10":"15.00","13":""}

Now, live_ids.grade = 9, so I want to be able to return 10.00... how do I do that?

item.SizePrice[live_ids.grade] will return value at that index — Abdul Basit
– Abdul Basit, Commented Feb 22, 2016 at 4:26

Hakan Kose · Accepted Answer · 2016-02-22 05:07:39Z

15

Here you check if the number is in the obj than execute else show error.

var obj = {
    "8":"15.00",
    "7":"20.00",
    "1":"6.00",
    "6":"11.00",
    "2":"7.00",
    "3":"8.00",
    "4":"9.00",
    "5":"10.00",
    "11":"20.00",
    "9":"10.00",
    "10":"15.00",
    "13":""
};

var number = 9;

if(number in obj){
    alert(obj[number])
} else {
    alert("This number does not exists")
}

answered Feb 22, 2016 at 5:07

Hakan Kose

1,6569 silver badges18 bronze badges

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Comments

abhay vyas · Accepted Answer · 2016-02-22 04:35:01Z

1

here is your solution...

<script type="text/javascript">
        var a={"k1": 100, "k2": 200, "k3": 300};
        var ky=prompt("enter key :");
        for (var k in a){
    if (a.hasOwnProperty(k)) {
        if(k==ky){
         alert("Key is " + k + ", value is" + a[k]);
        }
    }
}   
    </script>

answered Feb 22, 2016 at 4:35

abhay vyas

1462 bronze badges

Comments

guest271314 · Accepted Answer · 2016-02-22 04:24:31Z

0

item.SizePrice appears to be an Object, not an Array. You can use for..in loop on the object , break the loop after console.log() called

var items = {
    "8": "15.00",
    "7": "20.00",
    "1": "6.00",
    "6": "11.00",
    "2": "7.00",
    "3": "8.00",
    "4": "9.00",
    "5": "10.00",
    "11": "20.00",
    "9": "10.00",
    "10": "15.00",
    "13": ""
  },
  n = 9;

for (var prop in items) {
  if (items[n]) {
    console.log(items[n]);
    break;
  }
}

answered Feb 22, 2016 at 4:24

guest271314

1

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