node async only calls first function when inside node-lambda

Question

Using a vanilla node script like the following node async works just fine:

async = require('async');

async.waterfall([
    function (c) {
        console.log(1);
        c(null);
    },        
    function (c) {
        console.log(2);
        c(null);
    }       
  ]);

The above when run via node test.js prints out:

1
2

... as expected.

However if I place the code inside a node-lambda handler:

var async = require('async');

exports.handler = function( event, context ) {
  console.log( "==================================");

  async.waterfall([
    function (c) {
        console.log(1);
        c(null);
    },        
    function (c) {
        console.log(2);
        c(null);
    }        
  ]);

  console.log( "==================================");
  context.done( );
}

Only the first method is called when I run ./node_modules/.bin/node-lambda run

==================================
1
==================================

I'm using:

async 1.5.2,
node 5.5.0
node-lambda 0.1.5

isvforall · Accepted Answer · 2016-02-20 20:57:03Z

1

You are using asynchronous code. Apparently that code context.done( ); to finish the executing of the main function handler and other async code(second function in waterfall) cannot be executed, it did not have time enough, because the main function has been completed.

edited Feb 20, 2016 at 20:57

answered Feb 20, 2016 at 20:12

isvforall

8,9166 gold badges39 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

isvforall Over a year ago

@keithgould I've update the answer. Try to remove context.done( ); to test

keith gould Over a year ago

Boom! That was it @isvforall. Thank you.

Collectives™ on Stack Overflow

node async only calls first function when inside node-lambda

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related