how to convert json string to array in php?

Question

I have a json format and want to convert this to my customized format. Please help me for this conversion using PHP. Please help me out, how can i construct the above mentioned JSON array format. Here is my format:

 [{"label":"Food & Drinks","data":"2"},{"label":"Lifestyle","data":"1"}]

And want result in this format:

[["Food & Drinks", 2],["Lifestyle", 1]]

I know json decode. I want to customize this format to other format. — deepak bhardwaj
– deepak bhardwaj, Commented Feb 8, 2016 at 12:07
You just want to ignore the keys. I guess you want to use in some javascript. — Sougata Bose
– Sougata Bose, Commented Feb 8, 2016 at 12:09
Please provide some code where you can show what you have done until now. — Stephen Reindl
– Stephen Reindl, Commented Feb 8, 2016 at 13:02

Chetan Ameta · Accepted Answer · 2016-02-08 12:08:34Z

1

try below solution:

$json = '[{"label":"Food & Drinks","data":"2"},{"label":"Lifestyle","data":"1"}]';

$json_array = json_decode($json, true);

$new_array = array();

foreach($json_array as $arr){
    $new_array[] = array_values($arr);
}

print_r($new_array);

echo json_encode($new_array);

Output:

Array
(
    [0] => Array
        (
            [0] => Food & Drinks
            [1] => 2
        )

    [1] => Array
        (
            [0] => Lifestyle
            [1] => 1
        )

)
[["Food & Drinks","2"],["Lifestyle","1"]]

for more detail have alook at PHP: json_decode

answered Feb 8, 2016 at 12:08

Chetan Ameta

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Comments

Rajdeep Paul · Accepted Answer · 2016-02-08 12:30:35Z

1

The solution is:

First use json_decode() function to decode the json string
Then use array_map() function to apply a callback function(array_values() in this case) to each element of the given array

So your code should be like this:

// suppose $json is your json string
$arr = json_decode($json, true);
$newArr = array_map('array_values', $arr);

// display $newArr array
var_dump($newArr);

Here $newArr is your desired array.

edited Feb 8, 2016 at 12:30

answered Feb 8, 2016 at 12:13

Rajdeep Paul

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Mister M · Accepted Answer · 2016-02-08 12:07:50Z

0

$array = json_decode($json, true);
$result = array();
for($i=0; $i<sizeof($array); $i++){
    $result[] = array_values($array[$i]);
}

$result will be your expected result

answered Feb 8, 2016 at 12:07

Mister M

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Comments

danjam · Accepted Answer · 2016-02-08 12:24:52Z

0

Version that casts 'data' value to int

$json = '[{"label":"Food & Drinks","data":"2"},{"label":"Lifestyle","data":"1"}]';

$output = json_encode(array_map(function($v) {
    $v['data'] = (int) $v['data'];
    return array_values($v);
}, json_decode($json, true)));

// ["Food & Drinks",2],["Lifestyle",1]]
echo $output;

If int isn't needed

$output = json_encode(array_map('array_values', json_decode($json, true)));

answered Feb 8, 2016 at 12:24

danjam

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