I need to send integers greater than 255? Does anyone know how to do this?
3 Answers
Here's how (Thanks for the idea, Alex!):
Python:
def packIntegerAsULong(value):
"""Packs a python 4 byte unsigned integer to an arduino unsigned long"""
return struct.pack('I', value) #should check bounds
# To see what it looks like on python side
val = 15000
print binascii.hexlify(port.packIntegerAsULong(val))
# send and receive via pyserial
ser = serial.Serial(serialport, bps, timeout=1)
ser.write(packIntegerAsULong(val))
line = ser.readLine()
print line
Arduino:
unsigned long readULongFromBytes() {
union u_tag {
byte b[4];
unsigned long ulval;
} u;
u.b[0] = Serial.read();
u.b[1] = Serial.read();
u.b[2] = Serial.read();
u.b[3] = Serial.read();
return u.ulval;
}
unsigned long val = readULongFromBytes();
Serial.print(val, DEC); // send to python to check
Comments
Encode them into binary strings with Python's struct module. I don't know if arduino wants them little-endian or big-endian, but, if its docs aren't clear about this, a little experiment should easily settle the question;-).
1 Comment
toddstavish
Note: Arduino is little endian. You can swap endianess using struct module, I didn't have to though. Just for the record, I was on intel x86 mac osx 10.6.4. python 2.6.1, 64 bit.
Way easier :
crc_out = binascii.crc32(data_out) & 0xffffffff # create unsigned long
print "crc bytes written",arduino.write(struct.pack('<L', crc_out)) #L, I whatever u like to use just use 4 bytes value
unsigned long crc_python = 0;
for(uint8_t i=0;i<4;i++){
crc_python |= ((long) Serial.read() << (i*8));
}
No union needed and short !
Serial.print()perform an ASCII conversion (itoaor similar) or is it sending the number back out as binary? If the AVR receives the bytes backwards then transmits them back to your computer reversed again, it would look alright...